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Question

Question: How do you find the slope and the intercept for \[y = - 6x + 2\] ?...

How do you find the slope and the intercept for y=6x+2y = - 6x + 2 ?

Explanation

Solution

Hint : Here in this question, we have to plot the graph for the equation using the slope and the intercept. By substituting the x is equal to zero we can find the y intercept value and substituting y is equal to zero we can find the x intercept value. By equating the given equation to the general equation of line we can determine the slope.

Complete step-by-step answer :
The given equation is in the form of y=mx+by = mx + b , where m is slope and b is known as y-intercept. Slope means ratio of vertical change to the horizontal change i.e., ratio of change in y-axis or step size of y-axis to the change in x-axis or step size of x-axis. An intercept is a point where the straight line or a curve intersects the y-axis in a plane. If the point x is zero then the obtained point is a y -intercept.
Now consider the given equation y=6x+2y = - 6x + 2 -----------(1)
Substitute the value of x as 0 in equation (1), then we have
y=6(0)+2\Rightarrow y = - 6(0) + 2
On simplifying we get
y=2\Rightarrow y = 2
Therefore, y-intercept is (0, 2)
Substitute the value of y as 0 in the equation (1) then we have
0=6x+2\Rightarrow 0 = - 6x + 2
On simplifying we get

2=6x 2=6x x=13 x=0.33   \Rightarrow - 2 = - 6x \\\ \Rightarrow 2 = 6x \\\ \Rightarrow x = \dfrac{1}{3} \\\ \Rightarrow x = 0.33 \;

Therefore, x-intercept is (0.33, 0)
The general equation of a line is given by y=mx+by = mx + b , the b is the y-intercept and it is 2. On substituting we get y=mx+2y = mx + 2 ------ (2)
On comparing the equation (1) and equation (2) we get
m=6m = - 6
Therefore, the slope is 6 - 6
The graph for this is given below

So, the correct answer is “m = - 6”.

Note : The question is belonging to the concept of graph. By comparing the given equation to the equation of a line we calculate the slope and intercept. Or by choosing the value of x we can determine the value of y and then plotting the graphs for these points we obtain the result.