Question

How do you find the slope and intercept to graph $y = 14x$

Answer 1

Slope is the change in the value of $y$ with respect to $x$ in the equation. We can find the slope of the line by using the slope-intercept formula wherein we write the given equation in the form $y = mx + c$, where $m$ is the slope of the line and $c$ is the y-intercept.The intercepts are the points at which the line of an equation cuts the x-axis and y-axis. At the $x$ intercept on x-axis, $y = 0$. Similarly at the y-intercept on y-axis, $x = 0$.

Complete step by step solution:
We have to find the slope of the line given by the equation $y = 14x$.
We will use the slope-intercept formula to find the slope of the line.
The slope-intercept formula is given by $y = mx + c$.
On comparing the equation $y = 14x + 0$ with the standard form of the slope-intercept formula, we see that
$m = 14$ and $c = 0$
Thus, the slope of the given line is $14$
Also, the y-intercept is $0$. So, the point at which line will cut y-axis is $(0,{\kern 1pt} {\kern 1pt} 0)$
Now, we find the x-intercept by assuming $y = 0$ in the equation and evaluate the corresponding value of $x$. We assume here $y = 0$ because that the line will touch the x-axis at that point.
$y = 14x \\\ \Rightarrow 0 = 14x \\\ \Rightarrow x = 0 \\\$
Thus, we get the point as $(0,{\kern 1pt} {\kern 1pt} 0)$. This is the x-intercept of the graph of the given equation.
Hence, the slope of the given line is $14$, the x-intercept and y-intercept is both $(0,{\kern 1pt} {\kern 1pt} 0)$ or the origin.
This can be shown by way of the graph of $y = 14x$.

Note: For a straight line, if two points $A({x_1},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_1})$ and $B({x_2},{\kern 1pt} {\kern 1pt} {\kern 1pt} {y_2})$ are situated on the line, then by slope formula we can calculate the slope (m) as, $m = \dfrac{{{y_2} - {y_1}}}{{{x_2} - {x_1}}}$.