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Question: How do you find the slope and intercept to graph \(y = - \dfrac{1}{6}x + 6\)?...

How do you find the slope and intercept to graph y=16x+6y = - \dfrac{1}{6}x + 6?

Explanation

Solution

We will first write the general equation of a line which is given by y=mx+cy = mx + c and then find the slope by comparing and then we will put xx zero in given equation y=16x+6y = - \dfrac{1}{6}x + 6 to find yy - intercept and then y=0y = 0 to find the xx – intercept.

Complete step by step solution:
We are given that we are required to find the slope and the intercept of y=16x+6y = - \dfrac{1}{6}x + 6.
The general equation of a line is given by y=mx+cy = mx + c, where m is the slope of the line.
Now, we are given the line y=16x+6y = - \dfrac{1}{6}x + 6. If we compare this to the above mentioned line, we will then obtain: m=16m = - \dfrac{1}{6} and c = 6.
Therefore, the slope of the given line is 16 - \dfrac{1}{6}.
Now, we need to find the intercepts of the line y=16x+6y = - \dfrac{1}{6}x + 6.
Let us put in x=0x = 0 in the equation y=16x+6y = - \dfrac{1}{6}x + 6 to find the yy – intercept.
Putting x=0x = 0 in y=16x+6y = - \dfrac{1}{6}x + 6, we will then get y=6y = 6.
So, the yy – intercept of the given line is 6.
Let us put in y=0y = 0 in the equation y=16x+6y = - \dfrac{1}{6}x + 6 to find the xx – intercept.
Putting y=0y = 0 in y=16x+6y = - \dfrac{1}{6}x + 6, we will then get 6=16x - 6 = - \dfrac{1}{6}x.
Multiplying by – 6, we will then obtain the following:-
x=36\Rightarrow x = 36
So, the xx – intercept of the given line is 36.
Thus, we have the final answer as follows:-
The slope of the given line y=16x+6y = - \dfrac{1}{6}x + 6 is 16 - \dfrac{1}{6}.
The xx - intercept and the yy – intercept of the given line y=16x+6y = - \dfrac{1}{6}x + 6 is 6 and 36 respectively.

Note: The students must note that the xx and yy intercepts basically refer to the points where the line cuts the xx – axis and yy – axis at. The point where the coordinate axis cut the line at xx – axis is xx – intercept and yy – axis is yy – intercept.
The students must also know that the slope of a line is basically the tangent of the angle the line makes with the positive xx – axis. Here, in this question, we have tangent of the angle the given line is making with positive xx – axis is 16 - \dfrac{1}{6}.