Question

How do you find the roots of ${{x}^{2}}+3x+8=0$?

Answer 1

This is the question of algebraic expression as it consists of variables, coefficients, constants, and mathematical operations such as addition, subtraction, multiplication and division. In the given question of an expression, you just need to simplify the expression by using mathematical operations and evaluate further. The quadratic formula provides the solution for the quadratic equation:
$a{{x}^{2}}+bx+c=0$. In which a, b and c are the coefficient of respectively terms in the quadratic equation, as follows: Roots of the quadratic equation=$\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$.

Formula used:
The quadratic formula provides the solution for the quadratic equation:
$a{{x}^{2}}+bx+c=0$
In which a, b and c are the coefficient of respectively terms in the quadratic equation, as follows:
Roots of the quadratic equation= $\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$

Complete step by step answer:
Given quadratic equation,
${{x}^{2}}+3x+8=0$
The quadratic formula provides the solution for the quadratic equation:
$a{{x}^{2}}+bx+c=0$
In which a, b and c are the coefficient of respectively terms in the quadratic equation, as follows:
Roots of the quadratic equation= $\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}$
Determine the quadratic equation’s coefficients a, b and c:
The coefficient of the given quadratic equation ${{x}^{2}}+3x+8=0$ are,
a = 1
b = 3
c = 8
Plug these coefficient into the quadratic formula:
$\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}=\dfrac{-\left( 3 \right)\pm \sqrt{{{\left( 3 \right)}^{2}}-\left( 4\times 1\times 8 \right)}}{2\times 3}$
Solve exponents and square root, we get
$\Rightarrow \dfrac{-3\pm \sqrt{9-\left( 4\times 1\times 8 \right)}}{2\times 3}$
Performing any multiplication and division given in the formula,
$\Rightarrow \dfrac{-3\pm \sqrt{9-\left( 32 \right)}}{6}$
$\Rightarrow \dfrac{-3\pm \sqrt{-23}}{6}$
Simplifying the above we get
$\Rightarrow \dfrac{-3\pm \sqrt{-23}}{2}$
Here the value of discriminant i.e. $d=\sqrt{{{b}^{2}}-4ac}=\sqrt{-23}$ is negative.
Therefore no real solution because the discriminant is negative and the square root of a negative number is not a real number.
Hence, this equation has no real solution and only have imaginary roots.
Finding the imaginary roots;
Now, solving further
$\Rightarrow \dfrac{-3\pm \sqrt{-23}}{2}$
We got two values, i.e.
$\Rightarrow \dfrac{-3-\sqrt{-23}}{2}\ and\Rightarrow \dfrac{-3+\sqrt{-23}}{2}$
As we know that,
$i=imaginary\ number=\sqrt{-1}$
Thus,
The imaginary roots will be;
$\Rightarrow x=\dfrac{-3-i\sqrt{23}}{2}\ and\dfrac{-3+i\sqrt{23}}{2}$
Hence, this is the required answer.

Note: To solve or evaluation these types of expression, we need to know about the:
Solving quadratic equations using the formula
Simplifying radicals
Find prime factors
The general form of quadratic equation is $a{{x}^{2}}+bx+c=0$, where a b and c are the numerical coefficients or constants, and the value of $x$ is unknown one fundamental rule is that the value of a, the first constant can never be zero.