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Question

Question: How do you find the rectangular coordinates given \( (6,150^\circ ) \) ?...

How do you find the rectangular coordinates given (6,150)(6,150^\circ ) ?

Explanation

Solution

Hint : In this question, we are given an ordered pair, it is also known as the coordinates of a point. We see that the first one is an integer and the second one is an angle, so the given coordinates are of the form (r,θ)(r,\theta ) . There are two types of coordinates for plotting a point on the graph paper namely rectangular coordinate system and polar coordinate system. The given coordinates are the polar coordinates and we have to find the rectangular coordinates.
A right-angled triangle is formed by x, y and r, where x is the base, y is the height and r is the hypotenuse of the right-angled triangle, so by Pythagoras theorem, we get – x2+y2=r2{x^2} + {y^2} = {r^2} and by trigonometry we get –
cosθ=basehypotenuse=xx2+y2=xr x=rcosθ   \cos \theta = \dfrac{{base}}{{hypotenuse}} = \dfrac{x}{{\sqrt {{x^2} + {y^2}} }} = \dfrac{x}{r} \\\ \Rightarrow x = r\cos \theta \;
And similarly y=rsinθy = r\sin \theta
Using this information, we can find the value of x and y.

Complete step by step solution:
We are given the polar coordinates are (6,150)(6,150^\circ ) so we get r=6r = 6 and θ=150\theta = 150^\circ
We know that
x=rcosθ x=6cos(150) x=6cos(18030)   x = r\cos \theta \\\ \Rightarrow x = 6\cos (150^\circ ) \\\ \Rightarrow x = 6\cos (180^\circ - 30^\circ ) \;
We know cos(180x)=cosx\cos (180 - x) = - \cos x
x=6(cos30) x=6×32 x=33   \Rightarrow x = 6( - \cos 30^\circ ) \\\ \Rightarrow x = - 6 \times \dfrac{{\sqrt 3 }}{2} \\\ \Rightarrow x = - 3\sqrt 3 \;
y=rsinθ y=6sin(150) y=6(sin18030)   y = r\sin \theta \\\ \Rightarrow y = 6\sin (150^\circ ) \\\ \Rightarrow y = 6(\sin 180^\circ - 30^\circ ) \;
We know that sin(180x)=sinx\sin (180 - x) = \sin x
y=6sin30 y=6×12 y=3   \Rightarrow y = 6\sin 30^\circ \\\ \Rightarrow y = 6 \times \dfrac{1}{2} \\\ \Rightarrow y = 3 \;
Hence when the polar coordinates are (6,150)(6,150^\circ ) , the rectangular coordinates are (33,3)( - 3\sqrt 3 ,3)
So, the correct answer is “ (33,3)( - 3\sqrt 3 ,3) ”.

Note : The polar coordinate system is of the form (r,θ)(r,\theta ) where r is the distance of the point from the origin and θ\theta is the counter-clockwise angle between the line joining the point and the origin and the x-axis. The rectangular coordinate system is of the form (x,y)(x,y) and is the most commonly used coordinate system, where x is the distance of this point from the y-axis and y is the distance of the point from the x-axis.