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Question: How do you find the range given \(x=3-2t\) and \(y=2+3t\) for \(-2\le t\le 3\)?...

How do you find the range given x=32tx=3-2t and y=2+3ty=2+3t for 2t3-2\le t\le 3?

Explanation

Solution

First we need to know the meaning of the range of a parametric equation. Now, we will calculate the range of the values of x and y separately. To do this, first we will select the variable x and then we will write t in terms of x. Now, using the given condition 2t3-2\le t\le 3 we will find the range of x. Similarly we will find the range of values of y.

Complete step by step answer:
Here we have been provided with the parametric equation x=32tx=3-2t and y=2+3ty=2+3t with the condition 2t3-2\le t\le 3. We have to determine the range.
Since the given equation is a parametric equation so here the definitions of the domain and the range is slightly different from what we generally use for the function y=f(x)y=f\left( x \right). In parametric equations the domain is the set of values of t and the ranges are the sets of values of x and y. So, we need to determine the sets of values of x and y separately.
(1) Let us consider x=32tx=3-2t.
Now, we can write t in terms of x as:
t=3x2\Rightarrow t=\dfrac{3-x}{2}
2t3\because -2\le t\le 3
Substituting the value of t in terms of x we get,
23x23\Rightarrow -2\le \dfrac{3-x}{2}\le 3
Multiplying all the terms with 2 we get,
43x6 7x3 \begin{aligned} & \Rightarrow -4\le 3-x\le 6 \\\ & \Rightarrow -7\le -x\le 3 \\\ \end{aligned}
Multiplying all the terms with -1 and changing the direction of inequality because we are multiplying them with a negative number, we get,
3x7 \begin{aligned} & \Rightarrow -3\le x\le 7 \\\ \end{aligned}
Hence, the range of values of x is [3,7]\left[ -3,7 \right].
(2) Now, let us consider y=2+3ty=2+3t.
We can write t in terms of y as:
t=y23\Rightarrow t=\dfrac{y-2}{3}
2t3\because -2\le t\le 3
Substituting the value of t in terms of y we get,
2y233\Rightarrow -2\le \dfrac{y-2}{3}\le 3
Multiplying all the terms with 3 we get,$$$$
6y29 4y11 \begin{aligned} & \Rightarrow -6\le y-2\le 9 \\\ & \because -4\le y\le 11 \\\ \end{aligned}

Hence, the range of values of y is [4,11]\left[ -4,11 \right].

Note: You must remember the definition of domain and range for a parametric equation. In the above you cannot write the set of x values as the domain and the set of y values as the range because here we don’t have the function y=f(x)y=f\left( x \right) but the values of x and y depend on a third variable t. So, the domain of this given function will be the set of values of t.