Question
Question: How do you find the range given \(x=3-2t\) and \(y=2+3t\) for \(-2\le t\le 3\)?...
How do you find the range given x=3−2t and y=2+3t for −2≤t≤3?
Solution
First we need to know the meaning of the range of a parametric equation. Now, we will calculate the range of the values of x and y separately. To do this, first we will select the variable x and then we will write t in terms of x. Now, using the given condition −2≤t≤3 we will find the range of x. Similarly we will find the range of values of y.
Complete step by step answer:
Here we have been provided with the parametric equation x=3−2t and y=2+3t with the condition −2≤t≤3. We have to determine the range.
Since the given equation is a parametric equation so here the definitions of the domain and the range is slightly different from what we generally use for the function y=f(x). In parametric equations the domain is the set of values of t and the ranges are the sets of values of x and y. So, we need to determine the sets of values of x and y separately.
(1) Let us consider x=3−2t.
Now, we can write t in terms of x as:
⇒t=23−x
∵−2≤t≤3
Substituting the value of t in terms of x we get,
⇒−2≤23−x≤3
Multiplying all the terms with 2 we get,
⇒−4≤3−x≤6⇒−7≤−x≤3
Multiplying all the terms with -1 and changing the direction of inequality because we are multiplying them with a negative number, we get,
⇒−3≤x≤7
Hence, the range of values of x is [−3,7].
(2) Now, let us consider y=2+3t.
We can write t in terms of y as:
⇒t=3y−2
∵−2≤t≤3
Substituting the value of t in terms of y we get,
⇒−2≤3y−2≤3
Multiplying all the terms with 3 we get,$$$$
⇒−6≤y−2≤9∵−4≤y≤11
Hence, the range of values of y is [−4,11].
Note: You must remember the definition of domain and range for a parametric equation. In the above you cannot write the set of x values as the domain and the set of y values as the range because here we don’t have the function y=f(x) but the values of x and y depend on a third variable t. So, the domain of this given function will be the set of values of t.