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Question: How do you find the point-slope form of the equation of the line passing through the points \((-7, 0...

How do you find the point-slope form of the equation of the line passing through the points (7,0)(-7, 0) and (5,4)(5, 4)?

Explanation

Solution

To find the point-slope form consider the equation yy1=m(xx1)y - y_1 = m\left( {x - x_1} \right) in which the values of x1,y1x_1, y_1 and x2,y2x_2, y_2 are given. We need to find the value of m i.e., slope of a line by m=y2y2x2x1m = \dfrac{{y_2 - y_2}}{{x_2 - x_1}} in which all the points are known to us.

Formula used: yy1=m(xx1)y - y_1 = m\left( {x - x_1} \right)
In this,
x1x_1 = x-coordinate of the point
y1y_1 = y-coordinate of the point
m is the slope.

Complete step-by-step solution:
Let us write the given points as
(x1,y1)(x_1, y_1) = (-7, 0)
(x2,y2)(x_2, y_2) = (5, 4)
Using point slope form of a line as
yy1=m(xx1)\Rightarrow y - y_1 = m\left( {x - x_1} \right) ……………… 1
In which m is the slope and x1,y1x_1, y_1 are the given points on the line. Hence, we need to determine the value of m i.e., slope given by
m=y2y2x2x1\Rightarrow m = \dfrac{{y_2 - y_2}}{{x_2 - x_1}}
Substitute the values of each terms as
m=405(7)\Rightarrow m = \dfrac{{4 - 0}}{{5 - \left( { - 7} \right)}}
m=412\Rightarrow m = \dfrac{4}{{12}}
Hence, after simplifying the slope is
m=13\Rightarrow m = \dfrac{1}{3}
Now let us use equation 1 i.e., point slope form, in the equation we can use any values either x1,y1x_1, y_1 or x2,y2x_2, y_2.
Let us consider x2,y2x_2, y_2 as
yy2=m(xx2)\Rightarrow y - y_2 = m\left( {x - x_2} \right)
Let us substitute the values of slope m, x2x_2 and y2y_2 we get
y4=13(x5)\Rightarrow y - 4 = \dfrac{1}{3}\left( {x - 5} \right)

Therefore, the point-slope form of the equation of line passing through the points is y4=13(x5)y - 4 = \dfrac{1}{3}\left( {x - 5} \right).

Note: When the equation of a line using the slope of the line and a point through which the line passes, that equation can be found using the point-slope formula. The equation of a line whose slope is m and which passes through a point (x1,y1)(x_1, y_1) is found using the point-slope form and is given as yy1=m(xx1)y - y_1 = m\left( {x - x_1} \right).