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Question

Question: How do you find the period of \( y = \cos \left( {2x} \right) \) ?...

How do you find the period of y=cos(2x)y = \cos \left( {2x} \right) ?

Explanation

Solution

Hint : All the trigonometric functions are periodic in nature. This means that they repeat their values after a regular interval of time .The fundamental period of sine and cosine functions is 2π2\pi radians and that of tangent function is π\pi radians. Now, we have to find the fundamental period of the function y=cos(2x)y = \cos \left( {2x} \right) as given in the question.

Complete step by step solution:
In the problem given to us, we have to find the fundamental period of the function
y=cos(2x)y = \cos \left( {2x} \right) .
We know that the fundamental period of the cosine function
y=cos(x)y = \cos \left( x \right) is 2π2\pi radians.
Period of trigonometric functions can be easily computed using a technique.
The period of the trigonometric function y=cos(kx+c)y = \cos \left( {kx + c} \right) can be calculated easily by dividing the fundamental period of the original trigonometric function by the constant, k.
So, in the case of y=cos(2x)y = \cos \left( {2x} \right) , the period is (2π2)=π\left( {\dfrac{{2\pi }}{2}} \right) = \pi radians.
Hence, the period of y=cos(2x)y = \cos \left( {2x} \right) is π\pi radians
So, the correct answer is “ π\pi radians”.

Note : Periodic functions are the functions that repeat its value after a regular interval of time. Any function that does not repeat its value after a certain time interval is known as aperiodic function. Now, there can be multiple periods of a function. But only the smallest time interval after which the function repeats its value is called the fundamental period of the function.