Solveeit Logo

Question

Question: How do you find the period of \(\tan x\)?...

How do you find the period of tanx\tan x?

Explanation

Solution

We first explain the meaning of period for a given function. We draw the graph for our given function f(x)=tanxf\left( x \right)=\tan x. We try to find the value of the interval for which the graph goes into repetitive mode. We find the value from the graph and put that value in the equation of f(x+a)=f(x)f\left( x+a \right)=f\left( x \right). If the value satisfies that equation then the period value gets verified.

Complete step by step solution:
The period of tanx\tan x is π\pi . To find the period we need to use the graph of the ratio.

The line gets the repetition after the gap of π\pi . The period of a function is the value on which the graph repeats its value.
If f(x)f\left( x \right) be the given function then aa will be the period of the function when f(x+a)=f(x)f\left( x+a \right)=f\left( x \right).
We check the same for our given function f(x)=tanxf\left( x \right)=\tan x.
We need to find the value of f(x+π)f\left( x+\pi \right).
Therefore, f(x+π)=tan(x+2×π2)f\left( x+\pi \right)=\tan \left( x+2\times \dfrac{\pi }{2} \right). The angle goes in the third quadrant which is positive for tanx\tan x. Therefore, the sign of f(x+π)f\left( x+\pi \right) remains positive. Also, we are increasing the angle in an even multiple of π2\dfrac{\pi }{2}. This means the ratio remains fixed at tanx\tan x.
So, tan(x+2×π2)=tan(x)\tan \left( x+2\times \dfrac{\pi }{2} \right)=\tan \left( x \right).
The value for the increase of angle π\pi remains the same. This proves that the period of tanx\tan x is π\pi .

Note: Although the range of the function f(x)=tanxf\left( x \right)=\tan x is (,)\left( -\infty ,\infty \right). The period of the function remains π\pi for tanx,xR\tan x,\forall x\in \mathbb{R}. The primary domain for the function is (π2,π2)\left( -\dfrac{\pi }{2},\dfrac{\pi }{2} \right).