Solveeit Logo

Question

Question: How do you find the next two terms of the geometric sequence \[405,\,135,\,45,\,...\] ?...

How do you find the next two terms of the geometric sequence 405,135,45,...405,\,135,\,45,\,... ?

Explanation

Solution

First, we will learn about geometric sequence. A geometric sequence is a sequence or progression which contains non-zero numbers. In this sequence, each term is calculated by multiplying the previous number with a fixed common factor.

Formula used:
ai+1=ai×r{a_{i + 1}} = {a_i} \times r

Complete step by step answer:
According to the question, the sequence is a geometric sequence. So, we will try to solve the question by using the geometric sequence formula. The formula is:
ai+1=ai×r{a_{i + 1}} = {a_i} \times r
Here rr is the common factor. Now, we need to find rr. For that, we need to keep rr alone. So, we will shift the term ai{a_i}to the other side of the equation, and we get:
r=ai+1ai\Rightarrow r = \dfrac{{{a_{i + 1}}}}{{{a_i}}}
Now, we will put the values of the question according to the formula, and we get:
r=ai+1ai\Rightarrow r = \dfrac{{{a_{i + 1}}}}{{{a_i}}}
r=135405=45135\Rightarrow r = \dfrac{{135}}{{405}} = \dfrac{{45}}{{135}}
When we simplify the equation, we get:
r=13\Rightarrow r = \dfrac{1}{3}
Therefore, we get that rr is 13\dfrac{1}{3}.
Now, we know that the starting term here is a1{a_1}. So, we get that:
a1=405{a_1} = 405
The corresponding terms are a2,a3,a4,a5,...{a_2},\,{a_3},\,{a_4},\,{a_5},... and so on. To calculate the values of these terms, we need to apply the formula:
ai+1=ai×r{a_{i + 1}} = {a_i} \times r
When we calculate the values of these terms, we get:
a2=405×13{a_2} = 405 \times \dfrac{1}{3}
a2=135\Rightarrow{a_2} = 135
Similarly, we can calculate a3,a4,a5,...{a_3},\,{a_4},\,{a_5},\,..., and we get:
a3=135×13{a_3} = 135 \times \dfrac{1}{3}
a3=45\Rightarrow{a_3} = 45
a4=45×13\Rightarrow{a_4} = 45 \times \dfrac{1}{3}
a4=15\Rightarrow{a_4} = 15
a5=15×13\Rightarrow{a_5} = 15 \times \dfrac{1}{3}
a5=5\Rightarrow{a_5} = 5
So, now we can write the formula as:
an=405×(13)n1{a_n} = 405 \times {\left( {\dfrac{1}{3}} \right)^{n - 1}}

Therefore, the next two numbers of the geometric sequence 405,135,45,...405,\,135,\,45,\,... is 15and515\,\,and\,\,5.

Note: Many students make a mistake by calculating the wrong common factor that is rr, and most students get confused when rr is a fractional part. This question was easy, but there are difficult problems also. So, we need to always check whether the number is consistently true by multiplying the common ratio by other terms. This helps us verify the answer.