Question
Question: How do you find the limit of \[x\left( {{a^{\dfrac{1}{x}}} - 1} \right)\] as \[x \to \infty \]?...
How do you find the limit of xax1−1 as x→∞?
Solution
Apply L'Hospital’s rule to evaluate the equation. Let us know the statement of L'Hospital’s rule: It states that the limit when we divide one function by another is the same after we take the derivative of each function.
Formula used:
x→climg(x)f(x)=x→climg′(x)f′(x)
As where the limit of x is till infinity.
Complete step by step solution:
Let us write the given input
xax1−1
Rewriting with respect to limit as
x→∞limx1ax1−1
Hence, after simplifying it produces the indeterminate form 00
Now apply L'Hospitals rule
x→climg(x)f(x)=x→climg′(x)f′(x)
x→∞limx1ax1−1=x→∞limx2−1ax1⋅ln(a)⋅(x2−1)
x→∞limx1ax1−1=x→∞limax1ln(a)
x→∞limx1ax1−1=a0ln(a)
Implies that
x→∞limx1ax1−1=ln(a)
In which a0is 1, hence the limit of
xax1−1=ln(a)
Or in terms of log, we get logea.
Additional information:
Here are some of the properties to find the limit functions:
Sum Rule: This rule states that the limit of the sum of two functions is equal to the sum of their limits.
Constant Function Rule: The limit of a constant function is the constant.
Constant Multiple Rule: The limit of a constant times a function is equal to the product of the constant and the limit of the function.
Product Rule: This rule says that the limit of the product of two functions is the product of their limits (if they exist).
Quotient Rule: The limit of quotient of two functions is the quotient of their limits, provided that the limit in the denominator function is not zero
Note:
For a limit approaching the given value, the original functions must be differentiable on either side of value, but not necessarily at the value given. The limit of a quotient is equal to the quotient of the limits. The limit of a constant function is equal to the constant. The limit of a linear function is equal to the number x is approaching.