Question
Question: How do you find the limit of \[\dfrac{{\sin x}}{x}\] as \[x\] approaches to \[\infty \]?...
How do you find the limit of xsinx as x approaches to ∞?
Solution
To find the limit of the given function xsinx, apply squeeze theorem. As it deals with the limit values, rather than function values and if we have some function f(x), we define new functions h(x), g(x) such that h(x)⩽f(x)⩽g(x).
Complete step by step solution:
Let us write the given function as
xsinx
We'll use the Squeeze Theorem, which states that if we have some function f(x), we define new functions h(x), g(x) such that
h(x)⩽f(x)⩽g(x)
Then, we'll take
x→alimh(x), x→alimg(x)
If these limits are equal, then
x→alimf(x)=x→alimh(x)=x→alimg(x)
Hence, all the limits are equal.
We know that
−1⩽sinx⩽1
Then,
−x1⩽xsinx⩽x1
Take
x→∞lim−x1,
As x→∞, we get
x→∞lim−x1=−∞1=0
x→∞limx1=∞1=0
Hence,
x→∞limxsinx=0.
Additional information:
Here are some of the properties to find the limit functions:
Sum Rule: This rule states that the limit of the sum of two functions is equal to the sum of their limits.
Constant Function Rule: The limit of a constant function is the constant.
Constant Multiple Rule: The limit of a constant times a function is equal to the product of the constant and the limit of the function.
Product Rule: This rule says that the limit of the product of two functions is the product of their limits (if they exist).
Quotient Rule: The limit of quotient of two functions is the quotient of their limits, provided that the limit in the denominator function is not zero.
Note:
For a limit approaching the given value, the original functions must be differentiable on either side of value, but not necessarily at the value given. The limit of a quotient is equal to the quotient of the limits. The limit of a constant function is equal to the constant. The limit of a linear function is equal to the number x is approaching.