Solveeit Logo

Question

Question: How do you find the limit of \[\dfrac{{\sin x}}{x}\] as x approaches infinity?...

How do you find the limit of sinxx\dfrac{{\sin x}}{x} as x approaches infinity?

Explanation

Solution

Hint : Here in this question we need to find the limit for the function. Let we define the given function as f(x)f(x) and we apply the limit to it. The function will get closer and closer to some number. When the x approaches to infinity we need to find the limit of a function.

Complete step-by-step answer :
The idea of a limit is a basis of all calculus. The limit of a function is defined as let f(x)f(x)be a function defined on an interval that containsx=ax = a. Then we say thatlimxaf(x)=L\mathop {\lim }\limits_{x \to a} f(x) = L, if for every ε>0\varepsilon > 0there is some number δ>0\delta > 0such that f(x)L<ε\left| {f(x) - L} \right| < \varepsilon whenever0<xa<δ0 < \left| {x - a} \right| < \delta .
Here we have to find the value of the limit when x is infinity. The function is trigonometry. Let we define the given function asf(x)=sinxxf(x) = \dfrac{{\sin x}}{x}. Now we are going to apply the limit to the function f(x)f(x)so we have
limxf(x)=limxsinxx\mathop {\lim }\limits_{x \to \infty } f(x) = \mathop {\lim }\limits_{x \to \infty } \dfrac{{\sin x}}{x}
The function f(x)f(x) is a trigonometric function. As x approaches \infty we have to substitute the x as\infty .
When we consider the x value we will consider it as infinity. So by applying limit we have
limxf(x)=sin()\Rightarrow \mathop {\lim }\limits_{x \to \infty } f(x) = \dfrac{{\sin (\infty )}}{\infty }
The sine function of infinity is a finite value and the any number divided by infinity is zero so we have
limxf(x)=0\Rightarrow \mathop {\lim }\limits_{x \to \infty } f(x) = 0
Hence the when the x approaches to zero for the function sinxx\dfrac{{\sin x}}{x}
Therefore we have found the limit for the function f(x)=sinxxf(x) = \dfrac{{\sin x}}{x}
Hence limxsinxx=0\mathop {\lim }\limits_{x \to \infty } \dfrac{{\sin x}}{x} = 0
So, the correct answer is “0”.

Note : The function is of trigonometry and it is in form of fraction. The sine function of infinity is some finite value. When the x approaches to infinity, it implies that function is going to the infinity and the value will be zero. Infinity is a large number and doesn't know the exact value. Any number divided by infinity will be always zero.