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Question

Question: How do you find the inverse of \[f\left( x \right) = 3 - 2x\] ?...

How do you find the inverse of f(x)=32xf\left( x \right) = 3 - 2x ?

Explanation

Solution

Here in this question, we have to find the inverse of the given function y or f(x)f(x). The inverse of a function is denoted by f1(x){f^{ - 1}}(x). Here first we have to write the function in terms of x and then we have to solve for y using mathematics operations and simplification we get the required solution.

Complete step by step solution:
An inverse function or an anti-function is defined as a function, which can reverse into another function. In simple words, if any function “ff” takes xx to yy then, the inverse of “ff” will take yy to xx. If the function is denoted by ‘ff’ or ‘FF’, then the inverse function is denoted by f1{f^{ - 1}} or F1{F^{ - 1}}. i.e, If ff and gg are inverse functions, then f(x)=yf\left( x \right) = y if and only if g(y)=xg\left( y \right) = x. Consider the given function
f(x)=32xf\left( x \right) = 3 - 2x
y=32x\Rightarrow y = 3 - 2x--------(1)
switch the xx's and the yy's means replace xx as yy and yy as xx. i.e., f(x)f(x) is a substitute for "yy".

Equation (1) can be written as function of xxi.e.,
x=32yx = 3 - 2y------(2)
Now, to find the inverse we have to solve the equation (2) for yy.
Subtract 3 on both side by, then
x3=32y3x - 3 = 3 - 2y - 3
On simplification, we get
x3=2yx - 3 = - 2y
On rearranging
2y=x3- 2y = x - 3
Multiply both side by -1, then
2y=3x2y = 3 - x
Divide both side by 2
y=3x2y = \dfrac{{3 - x}}{2}
y=32x2\Rightarrow \,\,\,y = \dfrac{3}{2} - \dfrac{x}{2}
f1(x)=32x2\therefore\,\,\,{f^{ - 1}}\left( x \right) = \dfrac{3}{2} - \dfrac{x}{2}

Hence, the inverse of a function f(x)=32xf\left( x \right) = 3 - 2x is f1(x)=32x2{f^{ - 1}}\left( x \right) = \dfrac{3}{2} - \dfrac{x}{2}.

Note: We must know about the simple arithmetic operations. To find the inverse we swap the y variable into x and simplify the equation and determine the value for y. Since the given question contains a simple equation on simplification we obtain the result. While shifting the terms we must take care of signs.