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Question

Question: How do you find the inverse of an exponential function?...

How do you find the inverse of an exponential function?

Explanation

Solution

Here, we need to find the inverse of an exponential function. We will write the exponential function and we will assume that it is equal to yy. Then, we will use the rule of logarithms to simplify the equation for the particular variable xx. Then, we will interchange the variables to find the required inverse of the exponential function.

Complete step-by-step answer:
The exponential function is given by f(x)=abxf\left( x \right) = a{b^x}, where bb is a positive real number, and b1b \ne 1.
Let f(x)f\left( x \right) be equal to yy.
Therefore, we get
y=abxy = a{b^x}
We will use the rule of logarithms to simplify the equation for the particular variable xx.
First, we will isolate the exponential expression.
Dividing both sides of the equation by aa, we get
ya=bx\Rightarrow \dfrac{y}{a} = {b^x}
If an equation is of the form x=byx = {b^y}, it can be written using logarithms as y=logbxy = {\log _b}x, where x>0x > 0, b>0b > 0 and bb is not equal to 1.
Therefore, since ya=bx\dfrac{y}{a} = {b^x}, we get the equation
x=logb(ya)x = {\log _b}\left( {\dfrac{y}{a}} \right)
Now, we will interchange the variables to find the value of the inverse of the exponential function.
Interchanging the variable xx and variable yy, we get
y=logb(xa)\Rightarrow y = {\log _b}\left( {\dfrac{x}{a}} \right)
This is the value of the inverse of f(x)f\left( x \right).
Therefore, we get
f1(x)=logb(xa)\Rightarrow {f^{ - 1}}\left( x \right) = {\log _b}\left( {\dfrac{x}{a}} \right)
Therefore, the inverse of an exponential function abxa{b^x} is given by the expression logb(xa){\log _b}\left( {\dfrac{x}{a}} \right).

Note: We can verify the inverse by drawing the graph of an exponential function and its inverse.
Let the exponential function be y=2×3xy = 2 \times {3^x}.
We will draw the graphs of y=2×3xy = 2 \times {3^x} and its inverse, that is y=log3(x2)y = {\log _3}\left( {\dfrac{x}{2}} \right).
If the graphs are symmetrical along the line x=yx = y, then the two functions are the inverse of each other.
Drawing the graphs, we get

The red line is the graph of the equation x=yx = y, the blue curve is the graph of the equation y=2×3xy = 2 \times {3^x}, and the green curve is the graph of the equation y=log3(x2)y = {\log _3}\left( {\dfrac{x}{2}} \right).
We can observe that the graphs are symmetrical along the line x=yx = y.
Therefore, we have verified that y=2×3xy = 2 \times {3^x} is the inverse of y=log3(x2)y = {\log _3}\left( {\dfrac{x}{2}} \right), and y=log3(x2)y = {\log _3}\left( {\dfrac{x}{2}} \right) is the inverse of y=2×3xy = 2 \times {3^x}.