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Question

Question: How do you find the intercepts of \[y = 2{x^2} - 5x + 2\] ?...

How do you find the intercepts of y=2x25x+2y = 2{x^2} - 5x + 2 ?

Explanation

Solution

Hint : Here in this question, we have to plot the graph for the equation. By substituting the x is equal to zero we can find the y intercept value and substituting y is equal to zero we can find the x intercept value. By equating the given equation to the general equation of line we can determine the slope. Here we have found the x intercepts.

Complete step by step solution:
An intercept is a point where the straight line or a curve intersects the y-axis in a plane. If the point x is zero then the obtained point is a y -intercept.
Now consider the given equation y=2x25x+2y = 2{x^2} - 5x + 2 -----------(1)
Substitute the value of y as 0 in the equation (1) then we have
0=2x25x+2\Rightarrow 0 = 2{x^2} - 5x + 2
To determine the value of x we use the formula x=b±b24ac2ax = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}. Here the value of a is 2 and the value of b is -5 and the value of c is 2
Hence by substituting these values in the formula we get
x=(5)±(5)24(2)(2)2(2)\Rightarrow x = \dfrac{{ - ( - 5) \pm \sqrt {{{( - 5)}^2} - 4(2)(2)} }}{{2(2)}}
On simplifying we get
x=5±25164\Rightarrow x = \dfrac{{5 \pm \sqrt {25 - 16} }}{4}
On subtracting 16 from 25 we get
x=5±94\Rightarrow x = \dfrac{{5 \pm \sqrt 9 }}{4}
The square root of 9 is 3
x=5±34\Rightarrow x = \dfrac{{5 \pm 3}}{4}
Therefore, we have x=5+34x = \dfrac{{5 + 3}}{4} and x=534x = \dfrac{{5 - 3}}{4}
On simplifying we get
x=84=2x = \dfrac{8}{4} = 2 and x=534=12x = \dfrac{{5 - 3}}{4} = \dfrac{1}{2}
Therefore, x-intercept are (2,0)\left( {2,0} \right) and (12,0)\left( {\dfrac{1}{2},0} \right)
We can also find the y- intercept
Substitute the value of x as 0 in equation (1), then we have
y=2(0)25(0)+2\Rightarrow y = 2{(0)^2} - 5(0) + 2
On simplifying we get
y=2\Rightarrow y = 2
Therefore, y-intercept is (0,2)\left( {0,2} \right)
Hence we have found the x intercepts and also the y intercepts.
The graph for this is given below

Note : The question is belonging to the concept of graph. By comparing the given equation to the equation of a line we calculate the slope and intercept. Or by choosing the value of x we can determine the value of y and then plotting the graphs for these points we obtain the result.