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Question: How do you find the explicit formula for the following arithmetic sequence \[123,116,109,102,95\] ?...

How do you find the explicit formula for the following arithmetic sequence 123,116,109,102,95123,116,109,102,95 ?

Explanation

Solution

As seeing the given sequence, clearly it a decreasing series of sequence with a common difference of 7-7 here minus indicates decrement means it is an arithmetic sequence and definitely it will have a linear formula with a variable which depends on the term. Let consider its first term be aa and the common difference be dd that means the difference between nth{{n}^{th}} term and first term will be (n1)d(n-1)d as d is the common difference as all adjacent term has same difference this implies that the nth{{n}^{th}} term will be the sum of first term and (n1)d(n-1)d.

Complete step-by-step answer:
As in the given sequence, the first term let this be aa
a=123\Rightarrow a=123
And we can see that the difference between all the adjacent term is same, let this be dd
Since the series is decreasing that means the difference will be conventionally negative
d=7\Rightarrow d=-7
Now using the explicit formula for arithmetic sequence
an=a+(n1)d{{a}_{n}}=a+(n-1)d , where an=nth term of sequence{{a}_{n}}={{n}^{th}}\text{ }term\text{ of sequence}
Substituting all the values in this equation, we will get
an=123+(n1)(7)\Rightarrow {{a}_{n}}=123+(n-1)(-7)
an=123(n1)7\Rightarrow {{a}_{n}}=123-(n-1)7
an=1307n\Rightarrow {{a}_{n}}=130-7n
And clearly the sequence is decreasing
Hence, an=1307n{{a}_{n}}=130-7n.

Note: When we see an arithmetic sequence first find the common difference between the adjacent terms and then just apply the simple common sense that for the nth{{n}^{th}} term and first term the difference will be (n1)d(n-1)d and we will get that term by adding the first term in this difference.