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Question

Question: How do you find the exact values of \({{\tan }^{-1}}1\) ?...

How do you find the exact values of tan11{{\tan }^{-1}}1 ?

Explanation

Solution

To find the exact values of tan11{{\tan }^{-1}}1, we are going to first of all equate this inverse expression to θ\theta then we are going to take tan on both the sides of the equation. On doing that, you will need to use the property which says that multiplying a term with its inverse will give us the answer as 1. Then we should know the angle when tanθ\tan \theta takes the value 1.

Complete step-by-step answer:
In the above problem, we are asked to find the exact values of tan11{{\tan }^{-1}}1. To find the exact values of tan11{{\tan }^{-1}}1, we are going to equate this inverse expression to θ\theta . So, equating tan11{{\tan }^{-1}}1 to θ\theta we get,
tan11=θ{{\tan }^{-1}}1=\theta
In the above expression, the exact values are the values that θ\theta can take so for finding the values of θ\theta we are going to take tan on both the sides of the above equation and we get,
tantan11=tanθ\tan {{\tan }^{-1}}1=\tan \theta
Now, we know the property that when a term and its inverse gets multiplied then the result of this multiplication is 1 so the result of the expression tantan1\tan {{\tan }^{-1}} is equal to 1 so substituting the value 1 in place of tantan1\tan {{\tan }^{-1}} in the above equation we get,
1=tanθ1=\tan \theta
Now, we know that the θ\theta where tanθ\tan \theta will take value 1 is π4\dfrac{\pi }{4} so the value of θ\theta is equal to π4\dfrac{\pi }{4}.
Also, we know that tan is positive in third quadrant so another angle which will be possible is as follows:
π+π4\pi +\dfrac{\pi }{4}
Solving the above addition we get,
4π+π4=5π4\dfrac{4\pi +\pi }{4}=\dfrac{5\pi }{4}
Hence, the two exact values which we are getting are π4,5π4\dfrac{\pi }{4},\dfrac{5\pi }{4}.

Note: The mistake that could be possible in the above solution is that you might forget to write the other angle which lies in the third quadrant so make sure you have put this third quadrant angle also in the final solution.