Question
Question: How do you find the exact value of \(\tan x - 3\cot x = 0\) in the interval \(0 \leqslant x < 360? \...
How do you find the exact value of tanx−3cotx=0 in the interval 0⩽x<360?
Solution
Here we take 3cotx on the right-hand side and use the identity cotx=tanx1 . Then solve the equation to get the range of values of x . We know that tan60∘=3 and rest can be found using the identities.
Formula used: The following formula is used:
cotx=tanx1
Complete step-by-step solution:
The main equation can be written as:
tanx−3cotx=0
Transposing 3cotx on the right-hand side.
tanx=3cotx
Using the formula, we get:
tanx=3×tanx1
tan2x=3
Taking the square roots on both the sides.
Now, tanx=3ortanx=−3
Hence, x=60∘+k.180∘
Or it can be written in the form of x=120∘+k.180∘ where k is an integer.
Now, we can take all the values of x that lie between 0∘and360∘
Therefore x\, \in \,\left\\{ {{{60}^ \circ },\,{{120}^ \circ },\,{{240}^ \circ },\,{{300}^ \circ }} \right\\}
Note: There are three main functions in trigonometry i.e. Sine, Cosine and Tangent. There are certain trigonometric identities which can be stated as below:
sinx=cosecx1
cosx=secx1
tanx=cotx1
Trigonometric equations are those equations which contain trigonometric functions i.e. Sine, Cosine, Tangent, Cosecant, Secant and Cotangent.
The graph for the above equation tanx−3cotx=0 can be shown as below:
The graph shows that tanx and cotx meet at 4 different points in the range of 0∘and360∘ .
All the trigonometric identities are periodic functions of 2π .
That means for every integer k, it can be written as follows:
sin(x+2kπ)=sinx
cos(x+2kπ)=cosx
tan(x+kπ)=tanx