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Question: How do you find the exact value of \(\tan x - 3\cot x = 0\) in the interval \(0 \leqslant x < 360? \...

How do you find the exact value of tanx3cotx=0\tan x - 3\cot x = 0 in the interval 0x<360?0 \leqslant x < 360?

Explanation

Solution

Here we take 3cotx3\,\cot \,x on the right-hand side and use the identity cotx=1tanx\cot \,x = \,\dfrac{1}{{\tan \,x}} . Then solve the equation to get the range of values of xx . We know that tan60=3\tan \,{60^ \circ }\, = \,\sqrt 3 and rest can be found using the identities.

Formula used: The following formula is used:
cotx=1tanx\cot \,x = \,\dfrac{1}{{\tan \,x}}

Complete step-by-step solution:
The main equation can be written as:
tanx3cotx=0\tan \,x\, - \,3\,\cot \,x\, = 0
Transposing 3cotx3\cot x on the right-hand side.
tanx=3cotx\tan \,x\, = \,3\,\cot \,x
Using the formula, we get:
tanx=3×1tanx\tan \,x\, = \,3 \times \dfrac{1}{{\tan \,x}}
tan2x=3\tan {\,^2}x\, = \,3
Taking the square roots on both the sides.
Now, tanx=3ortanx=3\tan \,x\, = \,\sqrt 3 \,or\tan \,x\, = \, - \sqrt 3
Hence, x=60+k.180x\, = {60^ \circ }\, + \,k{.180^ \circ }
Or it can be written in the form of x=120+k.180x\, = \,{120^ \circ }\, + \,k.\,{180^ \circ } where kk is an integer.
Now, we can take all the values of xx that lie between 0and360{0^ \circ }\,and\,{360^ \circ }

Therefore x\, \in \,\left\\{ {{{60}^ \circ },\,{{120}^ \circ },\,{{240}^ \circ },\,{{300}^ \circ }} \right\\}

Note: There are three main functions in trigonometry i.e. Sine, Cosine and Tangent. There are certain trigonometric identities which can be stated as below:
sinx=1cosecx\sin x\, = \,\dfrac{1}{{\cos ec\,x}}
cosx=1secx\cos x\, = \,\dfrac{1}{{\sec \,x}}
tanx=1cotx\tan x\, = \dfrac{1}{{\cot x}}
Trigonometric equations are those equations which contain trigonometric functions i.e. Sine, Cosine, Tangent, Cosecant, Secant and Cotangent.
The graph for the above equation tanx3cotx=0\tan \,x\, - \,3\,\cot \,x\, = 0 can be shown as below:

The graph shows that tanx\tan \,x and cotx\cot \,x meet at 44 different points in the range of 0and360{0^ \circ }\,and\,{360^ \circ } .
All the trigonometric identities are periodic functions of 2π2\pi .
That means for every integer kk, it can be written as follows:
sin(x+2kπ)=sinx\sin \,(x\, + \,2k\pi )\, = \,\sin \,x
cos(x+2kπ)=cosx\cos \,(\,x\, + \,2k\pi )\, = \,\cos \,x
tan(x+kπ)=tanx\tan \,(x\, + \,k\pi )\, = \,\tan \,x