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Question

Question: How do you find the exact value of \(\sin (2x)\) using the double angle formula?...

How do you find the exact value of sin(2x)\sin (2x) using the double angle formula?

Explanation

Solution

In order to find the solution to this particular numerical the student should know what double angle formula is. How to simplify the double angle formula to its normal form. Basically when the angle of the trigonometric function is doubled, it is called double angle. But this doesn’t mean that the value would also double for example sin(60)2×sin(30)\sin (60) \ne 2 \times \sin (30). In order to evaluate the double angle , there are separate formulae for each trigonometric function. In this particular case we will have to use the double angle formula for sin(θ)\sin (\theta ).

Complete step-by-step answer:
In order to find the exact value of sin(2x)\sin (2x), we will first have to apply the double angle formula to this sin()\sin () function. The double angle formula is as follows:
sin(2x)=2sin(x)cos(x)\sin (2x) = 2\sin (x)\cos (x)
Now in order to find the value of sin(x)\sin (x) or cos(x)\cos (x) we need to know only 11 value out of sin(x)\sin (x) or cos(x)\cos (x). In order to know the other value we can use the formula
sin2x+cos2x=1{\sin ^2}x + {\cos ^2}x = 1.
Consider an example where we are only given the value of sin(x)\sin (x) and we have to find the value of sin(2x)\sin (2x). We can follow the below given method
sin(2x)=2sin(x)cos(x).........(1)\sin (2x) = 2\sin (x)\cos (x).........(1)
Since we are given the value of sin(x)\sin (x), we can bring cos(x)\cos (x) in terms of sin(x)\sin (x)
cos(x)=±1sin2x...........(2)\cos (x) = \pm \sqrt {1 - {{\sin }^2}x} ...........(2)
Thus the simplification would become
sin(2x)=±2sin(x)1sin2x.........(3)\sin (2x) = \pm 2\sin (x)\sqrt {1 - {{\sin }^2}x} .........(3)
Thus with the above equation we can find the exact value of sin(2x)\sin (2x).

Note: The students should remain cautious while calculating the value using the double angle formula. It is advisable that the students should learn the double angle formula or all trigonometric functions. The questions which could be asked would be of the following type: Find the value of sin(2x)\sin (2x) ,given cos(x)=257\cos (x) = \dfrac{{ - 25}}{7}.The students should also learn the basic triplets which would be used for calculating the values of the hypotenuse and then use them to calculate sin(x)&cos(x)\sin (x)\& \cos (x).