Question
Question: How do you find the exact value of \[\arcsin \left( \dfrac{1}{3} \right)\] ?...
How do you find the exact value of arcsin(31) ?
Solution
Here arcsine is used to denote the inverse of sine which is represented as sin−1 . The sine of any angle is the ratio of length of opposite side to the length of hypotenuse in a right-angle triangle. For example, graphically sin(2π)=1 . Since here we have to find arcsin of a transcendental value therefore to find the exact value, we need a calculator.
Complete answer:
In the question we have to find arcsin. Arcsin or sine inverse is sine inverse of a sine expression which gives the value of angle. It is equal to the ratio of length of hypotenuse to the length of the opposite side in a right-angle triangle. For example, sin−1(1)=2π .
We know that sin(6π)=21 so sine inverse of half will be equal to, sin−1(21)=6π . Here we are asked to find arcsin(31) which is sin−1(31) . So, we can say that the value of sin−1(31) must be less than 6π . But we know only standard radian values of trigonometric functions which are multiples of 0,6π,3π,2π . But here we are asked to find a value which will be less than 6π but greater than 0 so the value will be in the first quadrant. So, we will have to use a calculator to find the exact value of sin−1(31) . Enter the inverse sine mode in the calculator, enter the value of the number then obtain the result in radian or degree mode.
So, the value of sin−1(31) comes out to be 0.339836 rad.
Note: While solving the question of this type for non-transcendental values keep in mind the range and domain of the trigonometric functions. In the above question we can’t find the value by direct calculations therefore, we will use a calculator to find the correct and exact value. Also, when we are finding values of trigonometric functions, it is better to use a graph of that function.