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Question

Question: How do you find the exact value of \[\arcsin \left( \dfrac{1}{3} \right)\] ?...

How do you find the exact value of arcsin(13)\arcsin \left( \dfrac{1}{3} \right) ?

Explanation

Solution

Here arcsine is used to denote the inverse of sine which is represented as sin1{{\sin }^{-1}} . The sine of any angle is the ratio of length of opposite side to the length of hypotenuse in a right-angle triangle. For example, graphically sin(π2)=1\sin \left( \dfrac{\pi }{2} \right)=1 . Since here we have to find arcsin of a transcendental value therefore to find the exact value, we need a calculator.

Complete answer:
In the question we have to find arcsin. Arcsin or sine inverse is sine inverse of a sine expression which gives the value of angle. It is equal to the ratio of length of hypotenuse to the length of the opposite side in a right-angle triangle. For example, sin1(1)=π2{{\sin }^{-1}}(1)=\dfrac{\pi }{2} .
We know that sin(π6)=12\sin \left( \dfrac{\pi }{6} \right)=\dfrac{1}{2} so sine inverse of half will be equal to, sin1(12)=π6{{\sin }^{-1}}\left( \dfrac{1}{2} \right)=\dfrac{\pi }{6} . Here we are asked to find arcsin(13)\arcsin \left( \dfrac{1}{3} \right) which is sin1(13){{\sin }^{-1}}\left( \dfrac{1}{3} \right) . So, we can say that the value of sin1(13){{\sin }^{-1}}\left( \dfrac{1}{3} \right) must be less than π6\dfrac{\pi }{6} . But we know only standard radian values of trigonometric functions which are multiples of 0,π6,π3,π20,\dfrac{\pi }{6},\dfrac{\pi }{3},\dfrac{\pi }{2} . But here we are asked to find a value which will be less than π6\dfrac{\pi }{6} but greater than 00 so the value will be in the first quadrant. So, we will have to use a calculator to find the exact value of sin1(13){{\sin }^{-1}}\left( \dfrac{1}{3} \right) . Enter the inverse sine mode in the calculator, enter the value of the number then obtain the result in radian or degree mode.
So, the value of sin1(13){{\sin }^{-1}}\left( \dfrac{1}{3} \right) comes out to be 0.3398360.339836 rad.

Note: While solving the question of this type for non-transcendental values keep in mind the range and domain of the trigonometric functions. In the above question we can’t find the value by direct calculations therefore, we will use a calculator to find the correct and exact value. Also, when we are finding values of trigonometric functions, it is better to use a graph of that function.