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Question: How do you find the exact functional value \(\cos (\dfrac{{7\pi }}{{12}})\) using the cosine sum or ...

How do you find the exact functional value cos(7π12)\cos (\dfrac{{7\pi }}{{12}}) using the cosine sum or difference identity?

Explanation

Solution

Apply the formula of cosine sum cos(A+B)=cosAcosBsinAsinB\cos (A + B) = \cos A\cos B - \sin A\sin B.
In these questions try to break 7π12\dfrac{{7\pi }}{{12}} in two terms so that you can use the above formula and denote A and B.

Complete step by step answer:
Firstly let's break 7π12\dfrac{{7\pi }}{{12}} in two terms . We know 4+3=74 + 3 = 7 , so we will break 7π12\dfrac{{7\pi }}{{12}} in 4 and 3 . We cannot break it in other numbers because 12 is divisible by 4 and 3 and it is easier to calculate.
cos(7π12)=cos(4π12+3π12)\cos (\dfrac{{7\pi }}{{12}}) = \cos (\dfrac{{4\pi }}{{12}} + \dfrac{{3\pi }}{{12}})
Simplifying the above
cos(π3+π4)\Rightarrow \cos (\dfrac{\pi }{3} + \dfrac{\pi }{4})
Now , let’s take A as π4\dfrac{\pi }{4} and B as π3\dfrac{\pi }{3}
Put the values in the formula cos(A+B)=cosAcosBsinAsinB\cos (A + B) = \cos A\cos B - \sin A\sin B
Calculating cos and sin separately to avoid confusion
For cosA and cosB
cosπ4=12\cos \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }} and cosπ3=12\cos \dfrac{\pi }{3} = \dfrac{1}{2}
For sinA and sinB
sinπ4=12\sin \dfrac{\pi }{4} = \dfrac{1}{{\sqrt 2 }} and sinπ3=32\sin \dfrac{\pi }{3} = \dfrac{{\sqrt 3 }}{2}
cos(π3+π4)=cosπ4cosπ3sinπ4sinπ3\Rightarrow \cos (\dfrac{\pi }{3} + \dfrac{\pi }{4}) = \cos \dfrac{\pi }{4}\cos \dfrac{\pi }{3} - \sin \dfrac{\pi }{4}\sin \dfrac{\pi }{3}
Putting the values of cosine and sine
12121232\Rightarrow \dfrac{1}{{\sqrt 2 }} \cdot \dfrac{1}{2} - \dfrac{1}{{\sqrt 2 }}\dfrac{{\sqrt 3 }}{2}
Multiplying the above
122322\Rightarrow \dfrac{1}{{2\sqrt 2 }} - \dfrac{{\sqrt 3 }}{{2\sqrt 2 }}
Bothe have same denominators , subtract them
1322\Rightarrow \dfrac{{1 - \sqrt 3 }}{{2\sqrt 2 }}

Thus , value of cos(7π12)\cos (\dfrac{{7\pi }}{{12}}) is 1322\dfrac{{1 - \sqrt 3 }}{{2\sqrt 2 }}.

Additional information:
You can check from the calculator if the answer we obtained is correct or not.
For cos(7π12)\cos (\dfrac{{7\pi }}{{12}}) , finding the value using calculator we get -0.259
For 1322\dfrac{{1 - \sqrt 3 }}{{2\sqrt 2 }} , finding the value using calculator we get -0.259
Therefore our obtained value is correct.

Note:
Finding the exact value of the sine, cosine, or tangent of an angle is often easier if we can rewrite the given angle in terms of two angles that have known trigonometric values.
Therefore in the above question, we have used the cosine sum formula, if you have tried to break it into different identity it would be difficult to know the complex angles and it will take a long time.
For example when you break cos(7π12)\cos (\dfrac{{7\pi }}{{12}}) for difference identity , you will break 7 in 10 and 3 then you will get angles in 10π12\dfrac{{10\pi }}{{12}} or 5π12\dfrac{{5\pi }}{{12}} and π4\dfrac{\pi }{4} . Here finding the value of 5π12\dfrac{{5\pi }}{{12}} will be a long calculation.
So use the formulas accordingly.