Question
Question: How do you find the equation of a line with slope of \( - 3\) and contains the point \((0,\; - 3)?\)...
How do you find the equation of a line with slope of −3 and contains the point (0,−3)?
Solution
The equation of a line having slope equals to “m” and passing through a point having abscissa, which is the “x” value of the coordinate equals x1 and ordinate, which is the “y” value of the coordinate equals y1 is given as follows:
(y−y1)=m(x−x1)
Use this information to find the equation of the given line.
Formula used: Equation of a line when its slope and a passing point are given: (y−y1)=m(x−x1) where (x1,y1) is the coordinate of the passing point and m is the slope of the line.
Complete step-by-step solution:
Let the point be “A” from which the given line having slope of −3 is passing. Therefore the coordinates of point “A” will be given as A≡(0,−3)
Now we know that the equation of line having slope m and passing through a point having coordinates (x1,y1) is given as
(y−y1)=m(x−x1)
So we have given respective values of slope, m=−3 and the coordinates (x1,y1)=(0,−3) that is x1=0andy1=−3
Putting these values in the above equation in order to get the required equation of the line, we will get
⇒(y−(−3))=−3(x−0)
Simplifying this equation,
⇒(y+3)=−3x ⇒y+3x+3=0
Therefore y+3x+3=0 is the required equation for the line passing through (0,−3) and having slope of −3
Note: Slope of a line can be equals to zero or equals to infinity, according as the line is either parallel to x-axis or parallel to y-axis. Basically slope is the change of y values over x values we can also term it as “Rise over run”. Slope also has negative or positive values according to the nature of the line either decreasing or increasing.