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Question: How do you find the equation of a line passing through \(\left( 4,1 \right)\) with the slope \(m=-\d...

How do you find the equation of a line passing through (4,1)\left( 4,1 \right) with the slope m=12?m=-\dfrac{1}{2}?

Explanation

Solution

The equation of a line is typically written as y=mx+by=mx+b where mm is the slope and bb is the yy intercept. We can find the equation of a straight line when given the slope and a point on the line by using the formula y=m(xx1)y=m\left( x-{{x}_{1}} \right) where mm is slope and (yy1)\left( y-{{y}_{1}} \right) is point on the line. After putting value in the formula and solving then we can find the equation.

Complete step-by-step answer:
As per the question we have point (4,1)\left( 4,1 \right) and the slope m=12m=-\dfrac{1}{2} we have to find the equation of line using the given data.
The equation of a line is typically written as y=mx+by=mx+b where mm is slope and bb is yy intercept so we will not use this formula.
We will use point slope form for finding line equations.
Point slope formula yy1=m(xx1)y-{{y}_{1}}=m\left( x-{{x}_{1}} \right)
Where mm is the slope and (x1,y1)\left( {{x}_{1}},{{y}_{1}} \right) is the point.
\Rightarrow yy1=m(xx1)...(i)y-{{y}_{1}}=m\left( x-{{x}_{1}} \right)...(i)
\Rightarrow m=12(x1,y1)=(4,1)m=-\dfrac{1}{2}\left( {{x}_{1}},{{y}_{1}} \right)=\left( 4,1 \right)
Now put these value in the equation (i)(i)
\Rightarrow yy1=m(xx1)y-{{y}_{1}}=m\left( x-{{x}_{1}} \right)
\Rightarrow y1=12(x4)y-1=-\dfrac{1}{2}\left( x-4 \right)
\Rightarrow 2(y1)=1(x4)2\left( y-1 \right)=-1\left( x-4 \right)
\Rightarrow 2y2=1x+42y-2=-1x+4
\Rightarrow 2y=1x+4+22y=-1x+4+2
\Rightarrow 2y=1x+62y=-1x+6
\Rightarrow y=12x+3y=-\dfrac{1}{2}x+3
So, the equation of a line passing through (4,1)\left( 4,1 \right) with the slope m=12m=-\dfrac{1}{2} is
\Rightarrow y=12x+3y=-\dfrac{1}{2}x+3
By the point slope form we can find the equation of line.
Additional Information:
We can solve this by slope intercept form. We will solve one example in slope intercept form i.e. y=mx+by=mx+b where mm is the slope bb is the yy intercept and xx and yy stay. Written as xx and yy in the final equation.
Since we already have the slope our equation is now.
y=45x+by=-\dfrac{4}{5}x+b (because mm represents the slope so we plug. The slope’s value inform)
Now, we must find the yy-intercept. In order to find yy intercept we simply use the point given. By putting in 44 in the place of xx and 22 for yy
We will get,
\Rightarrow y=45x+by=-\dfrac{4}{5}x+b
\Rightarrow 2=45(4)+b2=-\dfrac{4}{5}\left( 4 \right)+b
\Rightarrow 2=165+b2=\dfrac{16}{5}+b
\Rightarrow b=45b=-\dfrac{4}{5}
So, we put the value of bb and the value of mm in the equation and we get our final equation
\Rightarrow y=45x45y=-\dfrac{4}{5}x-\dfrac{4}{5}
This method of solving is called a slope-intercept. From this we solve this with various methods.

Note:
First while solving this problem you should know the line intercept formula and write that correctly. If the given data is (0,2)\left( 0,2 \right) and (5,2)\left( 5,2 \right) then we will have another method solving various methods of solving this type of problem.