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Question: How do you find the distance between the point A (-3, 5) and the point B (4,-6) in the coordinate pl...

How do you find the distance between the point A (-3, 5) and the point B (4,-6) in the coordinate plane?

Explanation

Solution

This type of problem is based on the concept of geometry. We know that the distance between two points (x1,y1)\left( {{x}_{1}},{{y}_{1}} \right) and (x2,y2)\left( {{x}_{2}},{{y}_{2}} \right) in a coordinate plane is (x2x1)2+(y2y1)2\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}}.
Here, we have been given the points are A (-3, 5) and B (4,-6). By comparing, we get x1=3{{x}_{1}}=-3, y1=5{{y}_{1}}=5, x2=4{{x}_{2}}=4 and y2=6{{y}_{2}}=-6. Substitute these values in the formula to find the distance between A and B. Do necessary calculation and find the square root of the expression which is the required answer.

Complete step by step solution:
According to the question, we are asked to find the distance between A and B.
We have been given the points are A (-3, 5) and B (4,-6).
We know that the formula to find the distance between two points (x1,y1)\left( {{x}_{1}},{{y}_{1}} \right) and (x2,y2)\left( {{x}_{2}},{{y}_{2}} \right) is
d=(x2x1)2+(y2y1)2d=\sqrt{{{\left( {{x}_{2}}-{{x}_{1}} \right)}^{2}}+{{\left( {{y}_{2}}-{{y}_{1}} \right)}^{2}}} where d is the distance.
We know that the two pints are A (-3, 5) and B (4,-6).
By comparing with the known formula, we get
x1=3{{x}_{1}}=-3, y1=5{{y}_{1}}=5, x2=4{{x}_{2}}=4 and y2=6{{y}_{2}}=-6.
Let us now substitute the values in the distance formula.
d=(4(3))2+(65)2\Rightarrow d=\sqrt{{{\left( 4-\left( -3 \right) \right)}^{2}}+{{\left( -6-5 \right)}^{2}}}
We know that (x)=x-\left( -x \right)=x. Using this property, we get
d=(4+3)2+(65)2\Rightarrow d=\sqrt{{{\left( 4+3 \right)}^{2}}+{{\left( -6-5 \right)}^{2}}}
On further calculations, we get
d=72+(11)2d=\sqrt{{{7}^{2}}+{{\left( -11 \right)}^{2}}}
We know that square of 7 is 49 and square of -11 is 121.
On substituting in d, we get
d=49+121d=\sqrt{49+121}
We know that 49+121=170.
Therefore, we get
d=170d=\sqrt{170}
We cannot further simplify the above expression.
Therefore, the distance between the point A (-3, 5) and the point B (4,-6) in the coordinate plane is 170\sqrt{170} units.

Note: Whenever you get this type of problems, we should always know the formula for finding the distance in a coordinate plane. We never get a negative number in the square root. We should not forget to put units in the final answer without which the answer is incomplete. Avoid calculation mistakes based on sign conventions.