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Question

Question: How do you find the derivative of \(y = \sqrt x \) ?...

How do you find the derivative of y=xy = \sqrt x ?

Explanation

Solution

We will find out the derivative of the above term by differentiation, in which the power of a variable will become coefficient and the power of the variable will be subtracted by one and then simplify the terms.

Complete step by step solution:
To find out the derivative of y=xy = \sqrt x first of all we will simplify it as we know, x=x12\sqrt x = {x^{\dfrac{1}{2}}}
As y=x12......(1)y = {x^{\dfrac{1}{2}}}......(1)
Now, we will differentiate equation (1) on both sides.
dydx=12x121\dfrac{{dy}}{{dx}} = \dfrac{1}{2}{x^{\dfrac{1}{2} - 1}}
We will take L.C.M. of the powers of xx
12x122\Rightarrow \dfrac{1}{2}{x^{\dfrac{{1 - 2}}{2}}}
As we observe that we can perform subtraction operation in powers of xx
=12x12= \dfrac{1}{2}{x^{\dfrac{{ - 1}}{2}}}
As we know that, an=1an{a^{ - n}} = \dfrac{1}{{{a^n}}} so we can remove negative signs from power by taking it to the denominator.
=12×1x12= \dfrac{1}{2} \times \dfrac{1}{{{x^{\dfrac{1}{2}}}}}
As we know that x12=x{x^{\dfrac{1}{2}}} = \sqrt x
dydx=12×1x12x\dfrac{{dy}}{{dx}} = \dfrac{1}{2} \times \dfrac{1}{{\sqrt x }} \Rightarrow \dfrac{1}{{2\sqrt x }}

Hence, derivative of yy is 12x\dfrac{1}{{2\sqrt x }}

Note:
We should know that we can perform derivative by differentiation, and also remember the identity an=1an{a^{ - n}} = \dfrac{1}{{{a^n}}} which we use to change the negative sign present in the power of the variable into the positive sign.