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Question

Question: How do you find the derivative of \(y = \ln {e^x}\)....

How do you find the derivative of y=lnexy = \ln {e^x}.

Explanation

Solution

In order to determine the derivative of the above question with respect to variable xx, Apply the chain rule as we don’t have a single variable but we have a function as X=exX = {e^x}. So According to Chain rule ddx(lnX)=1X.ddx(X)\dfrac{d}{{dx}}(\ln X) = \dfrac{1}{X}.\dfrac{d}{{dx}}(X). Now using this rule and using the another rule of derivative ddx(lnx)=1x\dfrac{d}{{dx}}(\ln x) = \dfrac{1}{x}, you will obtain your desired result.

Formula used:
ddx(lnx)=1x\Rightarrow \dfrac{d}{{dx}}(\ln x) = \dfrac{1}{x}
ddx(ex)=ex\Rightarrow \dfrac{d}{{dx}}({e^x}) = {e^x}

Complete step by step answer:
We are Given a expression y=lnexy = \ln {e^x} and we have to find the derivative of this expression with respect to x.
dydx=ddx(lnex)\Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}(\ln {e^x})
Let’s Assume ex{e^x} as X
dydx=ddx(lnX)\Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{d}{{dx}}(\ln X)
Now Applying Chain rule to the above derivative which says that if we are not given a single variable xx and instead of it a function is given(XX) with the logarithm then the derivative will become
ddx(lnX)=1X.ddx(X)\Rightarrow \dfrac{d}{{dx}}(\ln X) = \dfrac{1}{X}.\dfrac{d}{{dx}}(X)
We know that Derivative of lnx\ln x is equal to 1x\dfrac{1}{x}
dydx=1X.ddx(X)\Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{1}{X}.\dfrac{d}{{dx}}(X)
Putting back XX
dydx=1ex.ddx(ex)\Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{1}{{{e^x}}}.\dfrac{d}{{dx}}({e^x})
Since ddx(ex)=ex\dfrac{d}{{dx}}({e^x}) = {e^x}
dydx=1ex.(ex) dydx=1  \Rightarrow \dfrac{{dy}}{{dx}} = \dfrac{1}{{{e^x}}}.({e^x}) \\\ \Rightarrow \dfrac{{dy}}{{dx}} = 1 \\\
Therefore , the derivative of y=lnexy = \ln {e^x} with respect to x is equal to 1.

Additional Information:
1. What is Differentiation?
It is a method by which we can find the derivative of the function .It is a process through which we can find the instantaneous rate of change in a function based on one of its variables.
Let y = f(x) be a function of x. So the rate of change of yy per unit change in xx is given by:
dydx\dfrac{{dy}}{{dx}}.
2. Value of constant ‘e’ is equal to 2.718282.71828.
3. A logarithm is basically the reverse of a power or we can say when we calculate a logarithm of any number, we actually undo an exponentiation.
4. Any multiplication inside the logarithm can be transformed into addition of two separate logarithm values.
logb(mn)=logb(m)+logb(n){\log _b}(mn) = {\log _b}(m) + {\log _b}(n)
5. Any division inside the logarithm can be transformed into subtraction of two separate logarithm values.
logb(mn)=logb(m)logb(n){\log _b}\left( {\dfrac{m}{n}} \right) = {\log _b}(m) - {\log _b}(n)
6. Any exponent value on anything inside the logarithm can be transformed and moved out of the logarithm as a multiplier and vice versa.
nlogm=logmnn\log m = \log {m^n}

Note: Logarithm is basically the inverse of exponent. Similarly differentiation is the inverse of integration. Chain rule is applied only when there is a need to differentiate a function not a single variable.