Question
Question: How do you find the derivative of \[{{\sin }^{7}}\left( x \right)\]?...
How do you find the derivative of sin7(x)?
Solution
Assume the function sinx as f(x), so that the given function gets converted into the form (f(x))n where n = 7. Now, differentiate the function with respect to the value x and use the formula dxd[f(x)n]=n×(f(x))n−1×f′(x) where f’(x) is the derivative of the assumed function f(x). Use the basic formula dxd(sinx)=cosx to get the answer.
Complete step by step solution:
Here, we have been provided with the function sin7(x) and we are asked to differentiate it. Let us assume the given function the as y. So, we have,
⇒f(x)=sinx
Therefore, assuming the given function as y, we have,
⇒y=(f(x))7
So, we have to differentiate the above function. Clearly, we can see that the above function is of the form y=(f(x))n, where n = 7, whose derivative is given by the power reduction formula given as: dxd[f(x)n]=n×(f(x))n−1×f′(x), where f’(x) is the derivative of f(x),so using this formula we get on differentiating both the sides with respect to the variable x,
⇒dxdy=7×(sinx)7−1×dxd[sinx]⇒dxdy=7×(sinx)6×dxd[sinx]⇒dxdy=7×sin6x×dxd[sinx]
Using the basic formula of the derivative of the sine function given as: dxd(sinx)=cosx, we get,
⇒dxdy=7×sin6x×cosx⇒dxdy=7sin6xcosx
Hence, the above relation is our answer.
Note: You must remember all the basic rules and formulas of differentiation like: - power reduction rule, product rule, chain rule, vu rule etc. as they make our question easy to solve. Remember the derivatives of some common functions like: - xn,ex, trigonometric functions, inverse trigonometric functions, logarithmic functions etc. as they are used frequently in calculus.