Question
Question: How do you find the derivative of \[s=t\sin t\]?...
How do you find the derivative of s=tsint?
Solution
Consider ‘s’ in the L.H.S as a function of t and differentiate both the sides with respect to the variable t. Consider ‘s’ as the product of an algebraic function and a trigonometric function. Now, apply the product rule of differentiation given as: - dtd(u×v)=udtdv+vdtdu. Here, consider, u = t and v=sint. Use the formula: - dtdsint=cost to simplify the derivative and get the answer.
Complete step by step solution:
Here, we have been provided with the function s=tsint and we are asked to differentiate it. Here we are going to use the product rule of differentiation to get the answer.
∵s=tsint
Clearly, we can see that we have ‘s’ as a function of t. Now, we can assume the given function as the product of an algebraic function (t) and a trigonometric function (sint). So, we have,
⇒s=t×sint
Let us assume t as ‘u’ and sint as ‘v’. So, we have,
⇒s=u×v
Differentiating both the sides with respect to t, we get,
⇒dtds=dtd(u×v)
Now, applying the product rule of differentiation given as: - dtd(u×v)=udtdv+vdtdu, we get,
⇒dtds=[udtdv+vdtdu]
Substituting the assumed values of u and v, we get,
⇒dtds=[tdtdsint+tdtdt]
We know that dtdsint=cost, so we have,