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Question

Question: How do you find the derivative of \[{{e}^{{{x}^{2}}}}\]?...

How do you find the derivative of ex2{{e}^{{{x}^{2}}}}?

Explanation

Solution

To solve the given question, we should know the derivatives of some of the functions, and how to differentiate composite functions. The functions whose derivatives we should know are ex{{e}^{x}} and x2{{x}^{2}}, their derivatives are ex&2x{{e}^{x}}\And 2x respectively. The composite functions are functions of the form f(g(x))f\left( g(x) \right), their derivative is found as, d(f(g(x)))dx=d(f(g(x)))d(g(x))d(g(x))dx\dfrac{d\left( f\left( g(x) \right) \right)}{dx}=\dfrac{d\left( f\left( g(x) \right) \right)}{d\left( g(x) \right)}\dfrac{d\left( g(x) \right)}{dx}. We will use these to find the derivative of the given function.

Complete step-by-step answer:
We know that the derivative of the composite function is evaluated as d(f(g(x)))dx=d(f(g(x)))d(g(x))d(g(x))dx\dfrac{d\left( f\left( g(x) \right) \right)}{dx}=\dfrac{d\left( f\left( g(x) \right) \right)}{d\left( g(x) \right)}\dfrac{d\left( g(x) \right)}{dx}.
We are given the function ex2{{e}^{{{x}^{2}}}}, we are asked to find its derivative. This is a composite function of the form f(g(x))f\left( g(x) \right), here we have f(x)=ex&g(x)=x2f(x)={{e}^{x}}\And g(x)={{x}^{2}}.
To find the derivative of the given function, we need to find d(ex2)d(x2)\dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{d\left( {{x}^{2}} \right)}, and d(x2)dx\dfrac{d\left( {{x}^{2}} \right)}{dx}.
We know that the derivative of ex{{e}^{x}} with respect to x is ex{{e}^{x}} itself. Thus, the derivative of ex2{{e}^{{{x}^{2}}}} with respect to x2{{x}^{2}} must be equal to ex2{{e}^{{{x}^{2}}}}. Hence, we get d(ex2)d(x2)=ex2\dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{d\left( {{x}^{2}} \right)}={{e}^{{{x}^{2}}}}. Also, the derivative of x2{{x}^{2}} with respect to x is 2x2x.
d(ex2)dx=d(ex2)d(x2)d(x2)dx\dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{dx}=\dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{d\left( {{x}^{2}} \right)}\dfrac{d\left( {{x}^{2}} \right)}{dx}
Substituting the expressions for the derivative, we get
d(ex2)dx=ex2×2x=2xex2\Rightarrow \dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{dx}={{e}^{{{x}^{2}}}}\times 2x=2x{{e}^{{{x}^{2}}}}
Thus, the derivative of the given function is 2xex22x{{e}^{{{x}^{2}}}}.

Note: Here we can express the given function in the form ef(x){{e}^{f(x)}}. There is a special method to find the derivatives of these types of functions. We can find their derivative using the following method,
d(ef(x))dx=ef(x)d(f(x))dx\dfrac{d\left( {{e}^{f(x)}} \right)}{dx}={{e}^{f(x)}}\dfrac{d\left( f(x) \right)}{dx}
For this question, we have f(x)=x2f(x)={{x}^{2}}. As we know that the derivative of x2{{x}^{2}} with respect to x is 2x2x. Using the above formula, we get
d(ex2)dx=ex2(2x)=2xex2\Rightarrow \dfrac{d\left( {{e}^{{{x}^{2}}}} \right)}{dx}={{e}^{{{x}^{2}}}}(2x)=2x{{e}^{{{x}^{2}}}}
Similarly, we can find the other functions of these types also.