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Question

Question: How do you find the derivative of \(\dfrac{4}{{\sqrt x }}\) ?...

How do you find the derivative of 4x\dfrac{4}{{\sqrt x }} ?

Explanation

Solution

To solve these types of questions, directly apply the rules of derivation to the given question. The rule to be applied depends on the form of the function given. After applying the appropriate derivative rule to the given question, simplify the expression obtained to get the final answer.

Formula Used: The following derivative rule can be applied to solve these questions:
If the given function can be written as f(x)=xnf(x) = {x^n} then its derivative can be given as ddx(xn)=nxn1\dfrac{d}{{dx}}({x^n}) = n{x^{n - 1}}

Complete step by step answer:
The given function whose derivative we have to find is 4x\dfrac{4}{{\sqrt x }} .
To find the derivative, first, simplify the given function in terms of exponents of xx which can be written as
4x=4x1/2\dfrac{4}{{\sqrt x }} = \dfrac{4}{{{x^{1/2}}}}
The above expression can be further simplified as
4x1/2=4x1/2\dfrac{4}{{{x^{1/2}}}} = 4{x^{ - 1/2}} (Using the law of exponents: 1xn=xn\dfrac{1}{{{x^n}}} = {x^{ - n}} ) ...(i)...(i)
Now compare the above expression to the derivative rule ddx(xn)=nxn1\dfrac{d}{{dx}}({x^n}) = n{x^{n - 1}}
Since 44 is a constant term it does not have to undergo derivation.
ddx(4x1/2)=4ddx(x1/2)\dfrac{d}{{dx}}(4{x^{ - 1/2}}) = 4\dfrac{d}{{dx}}({x^{ - 1/2}})
Applying the above mentioned derivative rule to the equation (i)(i) we get
4(12)(x121)\Rightarrow 4\left( { - \dfrac{1}{2}} \right)({x^{\dfrac{{ - 1}}{2} - 1}})
Simplifying the above expression we get
=4×12x32= 4 \times - \dfrac{1}{2}{x^{ - \dfrac{3}{2}}}
Further dividing the terms to get the simple expression,
=2x32= - 2{x^{ - \dfrac{3}{2}}}
=2x3= \dfrac{{ - 2}}{{\sqrt {{x^3}} }}
Hence, the derivative of 4x\dfrac{4}{{\sqrt x }} is 2x3\dfrac{{ - 2}}{{\sqrt {{x^3}} }} .

Therefore, ddx(4x)=2x3\dfrac{d}{{dx}}(\dfrac{4}{{\sqrt x }}) = \dfrac{{ - 2}}{{\sqrt {{x^3}} }}.

Additional information:
Differentiation is one of the two important concepts in the field of calculus, apart from integration. It can be defined as a process where we find the instantaneous rate of change in a function based on one of its variables. It is used to find the derivative of a given function. The general expression of derivative of a function f(x)=yf(x) = y can be given as f(x)=dydxf'(x) = \dfrac{{dy}}{{dx}} where dydx\dfrac{{dy}}{{dx}} can be defined as the rate of change of yywith respect to xx .

Note: While finding the derivative of such questions which include powers of xx in the denominator, one should remember the identity 1xn=xn\dfrac{1}{{{x^n}}} = {x^{ - n}} which we use to change the negative sign present in the power of the variable xx into the positive sign.