Question
Question: How do you find the derivation of \(f(x) = 4\sin x + 4{x^x}\)?...
How do you find the derivation of f(x)=4sinx+4xx?
Solution
According to the question we have to determine the derivation of the given function which is as given in the question is f(x)=4sinx+4xx. So, to determine the derivation of the given function first of all we have to apply the derivation in both hand sides of the expression.
Now, we have to determine the derivation of the function which is 4sinx but before finding the derivation we have to take out the constant term which is 4 as in the function and to determine the derivation we have to use the formula which is as mentioned below:
Formula used:
⇒dxdsinx=cosx.............(A)
Now, we have to find the derivation of the term 4xx but same as the previous step we have to take 4 out if the derivation which is a constant term and know to determine the derivation of xx we can not use the formula which is as mentioned below:
⇒dxdxn=nxn−1 because, on applying the formula we will get the derivation of xx as,
⇒dxdxx=x(xx−1) which is not possible.
Now, to determine the derivation of dxdxx we can use the following rule which is as mentioned as fg=eglogf where, f denotes f(x) and g denotes g(x) and log is the natural logarithm.
Now, as we know that it is possible to take the derivation of the function easily and which is because of the derivation of ex which is equal to ex so, we only have to multiply through by the derivative of what it is given in the power.
Complete step-by-step answer:
Step 1: To determine the derivation of the given function first of all we have to apply the derivation in the both hand sides in the expression as mentioned in the solution hint. Hence,
⇒dxdf(x)=dxd(4sinx+4xx)........(1)
Step 2: Now, we have to determine the derivation of the function which is 4sinx but before finding the derivation we have to take out the constant term which is 4 as in the function and to determine the derivation we have to use the formula (A) which is as mentioned in the solution hint. Hence,
⇒dxdsinx=cosx
Step 3: Now, we have to find the derivation of the term 4xx but same as the previous step we have to take 4 out if the derivation which is a constant term and know to determine the derivation of xx we can not use the formula which is as mentioned below:
⇒dxdxn=nxn−1 because, on applying the formula we will get the derivation of xx as,
⇒dxdxx=x(xx−1) which is not possible.
Step 4: Now, to determine the derivation of dxdxx we can use the following rule which is as mentioned as fg=eglogf where, f denotes f(x) and g denotes g(x) and log is the natural logarithm.
Now, as we know that it is possible to take the derivation of the function easily and which is because of the derivation of ex which is equal to ex so, we only have to multiply through by the derivative of what it is given in the power. Hence,
⇒dxdxx=dxd(exlogx)
Hence,
⇒dxd(exlogx)=exlogx(dxd(xlogx))
⇒dxd(xlogx)=1+logx
Step 5: But as we can see that there is no point leaving the result like that since we have to just go back to xx from exlogx. Hence,
⇒f′(x)=4cox+4xx(1+logx)
Hence, with the help of the formula (A) we have determined the value of the derivation f(x)=4sinx+4xx which is ⇒f′(x)=4cox+4xx(1+logx).
Note:
It is possible to take the derivation of the function easily and which is because of the derivation of ex which is equal to ex so, we only have to multiply through by the derivative of what it is given in the power.
To determine the derivation of the function which is 4sinx but before finding the derivation we have to take out the constant term which is 4.