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Question: How do you find the axis of symmetry and the maximum or minimum value of the function \(y={{x}^{2}}+...

How do you find the axis of symmetry and the maximum or minimum value of the function y=x2+3xy={{x}^{2}}+3x?

Explanation

Solution

For this problem we need to find the axis of symmetry and the maximum or minimum value of the given function. We can observe that the given equation is a parabola. For parabolas we will decide whether it has maximum or minimum by observing the sign of the x2{{x}^{2}} coefficient. So for the given equation we will check the sign of the x2{{x}^{2}} coefficient and write if it has a maximum or minimum value. For parabolas y=ax2+bx+cy=a{{x}^{2}}+bx+c we know that the minimum or maximum value is b2a-\dfrac{b}{2a}. So, we will compare the given equation with the standard equation y=ax2+bx+cy=a{{x}^{2}}+bx+c and calculate the required value.

Complete step by step answer:
Given equation y=x2+3xy={{x}^{2}}+3x.
We can observe that the coefficient of the x2{{x}^{2}} is +1+1. So, the given equation has a minimum value.
Comparing the given equation with the standard equation of parabola y=ax2+bx+cy=a{{x}^{2}}+bx+c, then we will get
a=1a=1, b=3b=3, c=0c=0.
Now the minimum value of the given equation is
xmin=b2a\Rightarrow {{x}_{\min }}=-\dfrac{b}{2a}
Substituting the values b=3b=3, a=1a=1 in the above equation, then we will get
xmin=32(1) xmin=32 \begin{aligned} & \Rightarrow {{x}_{\min }}=-\dfrac{3}{2\left( 1 \right)} \\\ & \Rightarrow {{x}_{\min }}=-\dfrac{3}{2} \\\ \end{aligned}
Now the ymin{{y}_{\min }} of the given equation can be calculated by substituting xmin{{x}_{\min }} in the given equation, then we will get
ymin=xmin2+3xmin ymin=(32)2+3(32) ymin=9492 ymin=94 \begin{aligned} & \Rightarrow {{y}_{\min }}=x_{\min }^{2}+3{{x}_{\min }} \\\ & \Rightarrow {{y}_{\min }}={{\left( -\dfrac{3}{2} \right)}^{2}}+3\left( -\dfrac{3}{2} \right) \\\ & \Rightarrow {{y}_{\min }}=\dfrac{9}{4}-\dfrac{9}{2} \\\ & \Rightarrow {{y}_{\min }}=-\dfrac{9}{4} \\\ \end{aligned}
Hence the minimum value of the given equation is (xmin,ymin)=(32,94)\left( {{x}_{\min }},{{y}_{\min }} \right)=\left( -\dfrac{3}{2},-\dfrac{9}{4} \right).
Now the axis of symmetry for the given equation is xmin=32{{x}_{\min }}=-\dfrac{3}{2} or x=32x=-\dfrac{3}{2}.
The diagram of the given equation with the calculated values is given by

Note: In this problem we have the coefficient of x2{{x}^{2}} as positive and we have calculated the minimum value. If we have the coefficient of the x2{{x}^{2}} then we will calculate the maximum value of the equation by using the same formula and the same procedure.