Question
Question: How do you find the amplitude, period, vertical and phase shift and graph for \[y=\cos \left( x-{{45...
How do you find the amplitude, period, vertical and phase shift and graph for y=cos(x−45∘)?
Solution
Convert the given angle in degrees into radian and write the function as y=cos(x−4π). Assume y=cosx as the reference function. Now, compare the given function y=cos(x−4π) with the general form: y=acos[b(x+c)]+d. Find the corresponding values of a, b, c and d and using these values find the vertical compression or stretch (a), also known as the amplitude, horizontal compression or stretch (b), horizontal shift (c), also known as the phase shift, and vertical shift (d) of the function. Now, to find the period of the function use the formula: T′=∣b∣T, where T is the period of cosx. Finally, draw the graph of the given function.
Complete step by step solution:
Here, we have been provided with the function y=cos(x−45∘) and we are asked to find its amplitude, time period and vertical and phase shift and we have to draw its graph. Generally we assume y=cosx as our reference function. We know that 45∘=4π radian, so we have the function as y=cos(x−4π).
Now, the general form of the cosine function is given as y=acos[b(x+c)]+d. Here, we have the vertical compression or stretch (a), also known as the amplitude, horizontal compression or stretch (b), horizontal shift (c), also known as the phase shift, and vertical shift (d) of the function. The descriptions for this transform are:
1. If ∣a∣>1 then vertical stretch takes place and if 0 < a < 1 then vertical compression takes place.
2. If ‘a’ is negative then the function is reflected about the x – axis.
3. If ∣b∣>1 then horizontal stretch takes place and if 0 < b < 1 then horizontal compression takes place.
4. If ‘b’ is negative then the function is reflected about y – axis.
5. If ‘c’ is negative then the function is shifted ∣c∣ units to the right and if ‘c’ is positive then the function is shifted ∣c∣ units to the left.
6. If ‘d’ is negative then the function is shifted ∣d∣ units down and if ‘d’ is positive then the function is shifted ∣d∣ units up.
Now, on comparing the given function y=cos(x−4π) with the general form y=acos[b(x+c)]+d, we have,
⇒a=1,b=1,c=−4π and d=0.
(i) Amplitude: - Amplitude of a function is defined as the minimum and maximum value that a function can approach. Clearly, the value of ‘a’ is 1 unit. Therefore the amplitude of the given function is 1 unit. Therefore, there will not be any vertical stretch or compression in the function provided.
(ii) Time period: - Time period of a function is defined as the interval of x after which the value of the function starts repeating itself. It is also simply called the period and the function is known as periodic function. The period of the function y=acos[b(x+c)]+d is given as T′=∣b∣T, where T is the period of cosx.
Now, we know that the period of cosx is T=2π, so we have,