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Question: How do you find the amplitude, period and phase shift for \(y=4\tan \left( 2x-\pi \right)\)?...

How do you find the amplitude, period and phase shift for y=4tan(2xπ)y=4\tan \left( 2x-\pi \right)?

Explanation

Solution

Now we know that amplitude of the function is nothing but maximum value of the function. Hence we will calculate the distance between axis and maximum point to find amplitude. Now for a function of the type atan(b(xc))a\tan \left( b\left( x-c \right) \right) the period is given by 2πb\dfrac{2\pi }{\left| b \right|} and the phase shift is given by c. Hence we will write the given function in the form atan(b(xc))a\tan \left( b\left( x-c \right) \right) and find the required values.

Complete step by step solution:
Now the given function is a trigonometric wave function.
For wave function we can define three properties.
Now if the function repeats the same value after every interval then the function is said to be periodic. All trigonometric functions are hence periodic. Now the length of such a smallest interval after which the function repeats its values is called period of the function.
Now the maximum height a function can attend from the axis is called the amplitude of the function. The amplitude of the function is also the length of the highest point or lowest point from the axis of the graph.
Now the horizontal shift of the function from the original function is known as phase shift.
Now the given function is of the form atan(b(xc))a\tan \left( b\left( x-c \right) \right) where a = 4, b = 2 and c=πc=\pi .
Now we know that the tan function ranges from -\infty to \infty . Hence we cannot calculate the amplitude of the function.
Now let us write the function in the form asin(b(x+c))a\sin \left( b\left( x+c \right) \right)
Hence we get, y=tan(2(xπ2))y=\tan \left( 2\left( x-\dfrac{\pi }{2} \right) \right)
Now for a function of the type atan(b(xc))a\tan \left( b\left( x-c \right) \right) the period is given by 2πb\dfrac{2\pi }{\left| b \right|} and phase shift is given by c. Hence the period of the function is 2π2=π\dfrac{2\pi }{2}=\pi and the phase shift is π2\dfrac{\pi }{2} .

Note: Now note that in general for a function of the type asin(b(x+c))a\sin \left( b\left( x+c \right) \right) we have the amplitude of the function as a. Now note that this is because the maximum value of sin and cos is 1 and the maximum value will be multiplied by a and hence we will get the maximum height as a. But this will not be the case in infinite functions and hence do not write the amplitude as a in case of tan.