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Question: How do you find slope, y-intercept, x-intercept of \(y = 3x\)?...

How do you find slope, y-intercept, x-intercept of y=3xy = 3x?

Explanation

Solution

For the given problem we will use the straight-line equation formula which is y=mx+cy = mx + c. Slope-intercept form can be stated as the other name for the above equation. By comparing, the equation with the given straight-line equation. And, then by simplifying you will get the required slope and intercept.

Complete step by step solution:
We have to solve the given equation y=3xy = 3x.
From the slope-intercept formula y=mx+cy = mx + c, we can determine the solution by comparing with the given equation. Here, m is the slope which is given as 3. And y-intercept that is c is 0 because we have no constant added to the term x in our problem.
To find the x-intercept, we have to substitute y as 0 and then solve it to find x:
0=3x\Rightarrow 0 = 3x [where y=0]
We can re-write the above equation, we get,
3x=0\Rightarrow 3x = 0
Dividing both sides by 3 and cancel all the common factors, we get,
3x3=03\Rightarrow \dfrac{{3x}}{3} = \dfrac{0}{3}
Now, simplify the above equation, we get,
x=0\Rightarrow x = 0

Therefore, the slope is 3 and x and the y-intercept is 0.

Additional Information:
The equation of the straight line is ax+by+c=0ax + by + c = 0, where x, y are variables and a, b, c are constants. The slope can also be determined with the help of tanθtan\theta . Straight line general or standard form is y=mx+cy = mx + c. And the slope-point form or the equation of a line with two points is (yy1)=m(xx1)(y - {y_1}) = m(x - {x_1})

Note:
y=mx+cy = mx + cis the generally straight-line equation, where m is slope or gradient, and y = c that is the value where the line cuts the y-axis. The c is intercepted on the y-axis. The equation of the line in the intercept form is xa+yb=1\dfrac{x}{a} + \dfrac{y}{b} = 1 where a is the x-intercept and b is the y-intercept.