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Question

Question: How do you find one-sided limits algebraically?...

How do you find one-sided limits algebraically?

Explanation

Solution

A one-sided limit is either of the two limits of a function f(x) of a real variable x as x approaches a specified point either from the left or from the right. When you have a left-hand limit or right-hand limit or both you can solve one-sided limits algebraically.

Complete step by step answer:
Let’s answer this question using examples.
Example 1 : limx1(x32)\mathop {\lim }\limits_{x \to 1} ({x^3} - 2)
In questions like this, you have to just put the value of x
(13)2\Rightarrow ({1^3}) - 2
12\Rightarrow 1 - 2
1\Rightarrow - 1
Let’s move on to the next example,
Example 2 : limx1(x29)x9\mathop {\lim }\limits_{x \to 1} \dfrac{{({x^2} - 9)}}{{x - 9}}
Directly putting the value x=1x = 1
We get 00\dfrac{0}{0} , this 00\dfrac{0}{0} is known as indeterminate .
In questions like this when you directly put the value you get the value in 00\dfrac{0}{0} form.
To solve this, we should simplify the question
You can apply the formula (ab)(a+b)=a2b2(a - b)(a + b) = {a^2} - {b^2}
limx1(x3)(x+3)(x3)\Rightarrow \mathop {\lim }\limits_{x \to 1} \dfrac{{(x - 3)(x + 3)}}{{(x - 3)}}
Numerator (x3)(x - 3) and denominator (x3)(x - 3) gets cancelled out
limx1(x+3)\Rightarrow \mathop {\lim }\limits_{x \to 1} (x + 3)
(1+3)\Rightarrow (1 + 3)
4\Rightarrow 4

Additional information:
You can use L'Hospital's Rule to solve limits that are indeterminate such as 00\dfrac{0}{0} and \dfrac{\infty }{\infty }.

Note:
One-sided limits are the same as normal limits, just restriction of x takes place so that it approaches from just one side.
xa+  x \to {a^ + }\;simply means x is approaching from the right side . Similarly , xa  x \to {a^ - }\; simply means x is approaching from the left side. When you have a graph of a particular function whose one-sided limit you want to calculate, graphs make it easier to calculate .
Limits exist when the right hand limit is equal to the left hand limit.