Question
Question: How do you find horizontal asymptotes for \[f\left( x \right)={{\tan }^{-1}}\left( x \right)\] ?...
How do you find horizontal asymptotes for f(x)=tan−1(x) ?
Solution
To solve these types of problems efficiently, one has to have a fair knowledge of graph theory and asymptotes of a graph. Knowledge of inverse functions is also necessary. Asymptotes are defined as the lines, which meet a curve at infinity. In these types of questions, we first plot the graph for the original trigonometric function, here which is tan(x) and then take its reflection about the line y=x to draw the graph of its inverse function. This is pretty much the straight forward rule to draw the graph for inverse functions.
Complete step by step answer:
Now starting off with the problem, we know that, when we try to calculate the value of tan(2π) or tan(−2π) or tan(2nπ) (where ‘n’ is any integer, positive or negative), it comes out to be undefined, which means that the vertical line x=n2π is an asymptote of the curve tan(x) . Now since the reflection of the curve y=tan(x) about the line y=x gives the graph for the inverse curve that is y=tan−1(x), reflection of x=n2π about the line y=x will also give the required equation of the horizontal asymptote. Thus we can safely say that y=tan−1(∞) and y=tan−1(−∞) will be the equations of the horizontal asymptotes of the equation y=tan−1(x) . We can further write that y=tan−1(tan(2nπ)) is the general equation for the asymptote. Thus,
y=2nπ , is the equation of the horizontal asymptote, where ‘n’ is any integer, positive or negative.
Note: We have to be very careful regarding the domain and range of the problem. In this question since no domain and range is given, the method done here is a more generalized one. After plotting the graph, we need to closely analyse for the lines which may meet the graph at infinity.