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Question

Question: How do you find b in \(y = mx + b\)?...

How do you find b in y=mx+by = mx + b?

Explanation

Solution

The standard form y=mx+by = mx + b is where m is the slope and b is the y-intercept. For calculating y-intercept we will take x=0x = 0 because it is equivalent to the y-coordinate of the point.

Complete step by step answer:
Let the slope = mm
Let the point = (x1,y1)({x_1},{y_1})
the standard form of y=mx+by = mx + b becomes y1=x1m+b{y_1} = {x_1}m + b
For calculating y-intercept we will take x=0x = 0 because it is equivalent to the y-coordinate of the point.
now you take the point (x,y)=(0,y1)(x,y) = (0,{y_1})that is on the line (has to be on the line) and replace x and y in the equation with it.
The equation becomes
y1=0×m+b y1=b  {y_1} = 0 \times m + b \\\ {y_1} = b \\\
So this way you can find y-intercept.

Note: if two points were given in questions so you can directly use the below equation.
b=x2y1x1y2x2x1b = \dfrac{{{x_2}{y_1} - {x_1}{y_2}}}{{{x_2} - {x_1}}}
Here, (x1,y1)({x_1},{y_1}) and (x2,y2)({x_2},{y_2}) are points on line
You do not have to memorize this formula, we can let one of two points be on the y-axis.
In this case, let that be the first point,
So x1=0{x_1} = 0
So here again we get y1=b{y_1} = b.