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Question

Question: How do you find \(a=2b+c\) given \(b=<6,3>\) and \(c=<-4,8>\)?...

How do you find a=2b+ca=2b+c given b=<6,3>b=<6,3> and c=<4,8>c=<-4,8>?

Explanation

Solution

In the above question, we have been given to vectors bb and cc in the matrix representation. Firstly we need to convert them into the standard representation in terms of i^\widehat{i} and j^\widehat{j} unit vectors. The third vector aa is related to the given vectors bb and cc by the vector equation a=2b+ca=2b+c. On substituting the vectors bb and cc into the given vector equation, and on adding the corresponding components of the unit vectors i^\widehat{i} and j^\widehat{j}, we will get the required vector aa. Finally we have to write the vector aa in the matrix form, as is given in the above question.

Complete step by step solution:
According to the above question, the two vectors given to us are b=<6,3>b=<6,3> and c=<4,8>c=<-4,8>. These vectors have been given in the matrix representation. Since they have two components, they must be expressed in the form of the unit vectors i^\widehat{i} and j^\widehat{j}. So they can be expressed in the unit vector representation as follows.

& \Rightarrow b=6\widehat{i}+3\widehat{j}........\left( i \right) \\\ & \Rightarrow c=-4\widehat{i}+8\widehat{j}......\left( ii \right) \\\ \end{aligned}$$ Now, in the above question, the third vector $a$ is related to the vectors $b$ and $c$ by the relation $\Rightarrow a=2b+c$ Substituting the equations (i) and (ii) into the above equation, we get $$\begin{aligned} & \Rightarrow a=2\left( 6\widehat{i}+3\widehat{j} \right)+\left( -4\widehat{i}+8\widehat{j} \right) \\\ & \Rightarrow a=12\widehat{i}+6\widehat{j}-4\widehat{i}+8\widehat{j} \\\ & \Rightarrow a=8\widehat{i}+14\widehat{j} \\\ \end{aligned}$$ The above vector can be expressed in the matrix representation as $\Rightarrow a=<8,14>$ Hence, the vector $a$ is found as $<8,14>$ **Note:** We could directly substitute the matrix forms of the given vectors $b$ and $c$ into the given vector equation $a=2b+c$. But converting them into the standard unit vector form is more convenient. Also, do not forget to convert the unit vector form of the vector $a$ into the matrix form. This is because the unit vectors $$\widehat{i}$$ and $\widehat{j}$ were assumed by us and not given in the question.