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Question

Question: How do you factor \[y=4{{x}^{2}}-36x+81\] ?...

How do you factor y=4x236x+81y=4{{x}^{2}}-36x+81 ?

Explanation

Solution

From the question given equation is y=4x236x+81y=4{{x}^{2}}-36x+81.For answering this question we will use factorization. Factorization is the process of deriving factors of a number which divides the given number evenly. Factorization is the process of reducing the bracket of a reducing the bracket of a quadratic equation, instead of expanding the bracket and converting the equation to a product of factors which cannot be reduced further. There are many methods for the factorization process. Now, we will do the given question by the method of splitting the constant and doing the sum product pattern.

Complete step by step solution:
Now considering from the question we have an expression y=4x236x+81y=4{{x}^{2}}-36x+81 for which we need to derive the factors.
We can factor the y=4x236x+81y=4{{x}^{2}}-36x+81 by below method:
Given equation is in the form of ax2+bx+c=0a{{x}^{2}}+bx+c=0
First, we have to divide 324324into the product of the two numbers and the Sum of those two numbers must be equal to the coefficient ofxx.
Now, 324324 can be split into the product of the two numbers.
324324can be split into product of 18-18and 18-18
Their sum is also equal to 36-36which is equal to the coefficient ofxx.
4x236x+814{{x}^{2}}-36x+81
4x236x+81=0\Rightarrow 4{{x}^{2}}-36x+81=0
4x218x18x+81=0\Rightarrow 4{{x}^{2}}-18x-18x+81=0
2x(2x9)9(2x9)=0\Rightarrow 2x\left( 2x-9 \right)-9\left( 2x-9 \right)=0
(2x9)(2x9)=0\Rightarrow \left( 2x-9 \right)\left( 2x-9 \right)=0
(2x9)2=0\Rightarrow {{\left( 2x-9 \right)}^{2}}=0
x=92\Rightarrow x=\dfrac{9}{2}
Therefore x=92 x=\dfrac{9}{2} is the factors of 4x236x+814{{x}^{2}}-36x+81

Note: During answering questions of this type students can recognise as a perfect square trinomial. In general, (a±b)2=a2±2ab+b2{{\left( a\pm b \right)}^{2}}={{a}^{2}}\pm 2ab+{{b}^{2}} In the above question student can notice that 4x2=(2x)24{{x}^{2}}={{\left( 2x \right)}^{2}} and 81=9281={{9}^{2}} are both perfect squares, so the question is if we let a=2xa=2x and b=9b=9 then does ±2ab\pm 2ab match the middle term 36-36 with a minus sign.
Hence: (2x9)2=4x236x+81{{\left( 2x-9 \right)}^{2}}=4{{x}^{2}}-36x+81