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Question

Question: How do you factor \( {x^2} - 5x? \)...

How do you factor x25x?{x^2} - 5x?

Explanation

Solution

Check for the common factor between each term of the expression, and then take the common factor out of the term then rewrite the expression in its factored form. Find common factors by splitting the terms into their factors.

Complete step by step solution:
In order to factorize an expression, we should firstly check for any common factor between all the terms of the expression, so now checking for common factors between the terms x2  and  5x{x^2}\;{\text{and}}\;5x by splitting them in their factors as following

We can write x2=x×x  and  5x=5×x{x^2} = x \times x\;{\text{and}}\;5x = 5 \times x
We can see that there is a common factor between them which is equal to xx

Now taking xx common from the given expression we will get
=x25x =x(x5)  = {x^2} - 5x \\\ = x(x - 5) \\\
Therefore the required factored form of the expression x25x{x^2} - 5x is x(x5)x(x - 5)

We should check our answer by performing the multiplication between resultant factors. So multiplying
xx with x5x - 5 , we will get
=x×(x5)= x \times (x - 5)

Using the distributive property of multiplication to multiply the terms further
=x×xx×5 =x25x  = x \times x - x \times 5 \\\ = {x^2} - 5x \\\

So we got the given expression after the multiplication of terms of the resultant factors. It means our factorization and result is correct.

Note: We can also solve this by sum product method for factorization of algebraic expressions. Sum product method can only be applied for quadratic polynomial expressions, it can be understood as a quadratic polynomial expression ax2+bx+ca{x^2} + bx + c where a,  b  and  ca,\;b\;{\text{and}}\;c are constant, can be factorized by splitting the middle term i.e. the coefficient of xx in such a way that the multiplication of the separated terms should be equal to product of a  and  ca\;{\text{and}}\;c and their sum should be equal to bb Try this method by yourself for this question. Hint: Take value of c=0c = 0