Question
Question: How do you factor the trinomial \[{{x}^{2}}-7x+6\]?...
How do you factor the trinomial x2−7x+6?
Solution
Use the middle term split method to factorize x2−7x+6. Split -7x into two terms in such a way that their sum is -7x and product is 6x2. For this process, find the prime factors of 6 and combine them in such a manner so that we can get our condition satisfied. Finally, take the common terms together and write x2−7x+6 as a product of two terms given as (x−a)(x−b). Here, ‘a’ and ‘b’ are called zeroes of the polynomial.
Complete step by step answer:
Here, we have been asked to factorize the polynomial: x2−7x+6 which is quadratic in nature.
Let us use the middle term split method for the factorization.
It says that we have to split the middle term which is -7x into two terms such that their sum is -7x and product is 6x2. To do this, first we need to find all the prime factors of 6. So, let us find.
We know that 6 can be written as: - 6=2×3 as the product of its primes. Now, we have to group 2 and 3 such that our conditions of the middle term split method is satisfied. So, we have,
(i) (−x)+(−6x)=−7x
(ii) (−x)×(−6x)=6x2
Hence, both the conditions of the middle term split method is satisfied and therefore, the quadratic polynomial can be written as: -
⇒x2−7x+6=x2−x−6x+6
Grouping the term together we have,
⇒x2−7x+6=x(x−1)−6(x−1)
Taking (x−1) common we have,
⇒x2−7x+6=(x−1)(x−6)
Hence, (x−1)(x−6) is the factored form of the given quadratic polynomial.
Note:
One may note that we can use another method for the factorization. The Discriminant method can also be applied to solve the question. What we will do is we will find the solution of the quadratic equation using discriminant method. The values of x obtained will be assumed as x = a and x = b. Finally, we will consider the product (x−a)(x−b) to get the factored form.