Question
Question: How do you factor the quadratic equation \[12{{x}^{2}}+13x-4\]?...
How do you factor the quadratic equation 12x2+13x−4?
Solution
Apply the middle term split method to factorize 12x2+13x−4. Split 13x into two parts in such a way that their sum is 13x and the product is −48x2. For this process find the prime factors of 48 and combine them in such a way so that we can get our conditions satisfied. Finally, take the common terms together and write 12x2+13x−4 as a product of two terms given as (x−a)(x−b). Here, ‘a’ and ‘b’ are called zeroes of the polynomial.
Complete answer:
Here, we have been asked to factorize the quadratic polynomial: 12x2+13x−4.
Let us use the middle term split method for the factorization. It states that we have to split the middle term which is 13x into two terms such that their sum 13x and product is equal to the product of constant term (-4) and 12x2, i.e., −48x2. To do this, first we need to find all the prime factors of 48. So, let us find.
We know that 48 can be written as: - 48=2×2×2×2×3 as the product of its primes. Now, we have to group these four 2’s and one 3 such that our conditions of the middle term split method is satisfied. So, we have,
(i) 16x+(−3x)=13x
(ii) 16x×(−3x)=−48x2
Hence, both the conditions of the middle term split method are satisfied. So, the quadratic polynomial can be written as: -