Question
Question: How do you factor \(64{x^4} + x{y^3}\) ?...
How do you factor 64x4+xy3 ?
Solution
To order to determine the factors of the above quadratic equation using the identity (A2−B2)=(A−B)(A+B)
Formula:
(A3+B3)=(A+B)(A2−A.B+B2)
Complete step by step solution:
Given a quadratic equation 64x4+xy3,let it be f(x)
f(x)=64x4+xy3
To simplify the above expression, pull out x from both of the terms.
f(x)=(x)(64x3+y3)
To find the factorization we’ll be writing the expression as
f(x)=(x)((4x)3+(y)3)
Consider 4xas A and yas B and Applying Identity (A3+B3)=(A+B)(A2−A.B+B2)
Now our equation becomes
f(x)=(x)(4x+y)(16x2−4xy+y2)
Hence, we have successfully factorized our mathematical equation.
Therefore, the factors are(x) ,(4x+y),and(16x2−4xy+y2).
Additional Information:
Quadratic Equation: A quadratic equation is a equation which can be represented in the form of ax2+bx+cwhere xis the unknown variable and a,b,c are the numbers known where a=0.If a=0then the equation will become a linear equation and will no longer be quadratic .
The degree of the quadratic equation is of the order 2.
Every Quadratic equation has 2 roots.
Discriminant: D=b2−4ac
Using Discriminant, we can find out the nature of the roots
If D is equal to zero, then both of the roots will be the same and real.
If D is a positive number then, both of the roots are real solutions.
If D is a negative number, then the root are the pair of complex solutions
To find factors of Quadratic equation
x1=2a−b+b2−4ac and x2=2a−b−b2−4ac
x1,x2 are root to quadratic equation ax2+bx+c
Hence the factors will be (x−x1)and(x−x2).
Note:
1. One must be careful while calculating the answer as calculation error may come.
2.Don’t forget to compare the given quadratic equation with the standard one every time.