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Question

Question: How do you factor \[3{x^2} - 12x\]?...

How do you factor 3x212x3{x^2} - 12x?

Explanation

Solution

Here in this question, we have to find the factors, the given equation is in the form of a quadratic equation. This is a quadratic equation for the variable x. By using the formula x=b±b24ac2ax = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}, we can determine the roots of the equation and factors are given by (x – root1) (x – root 2)

Complete step-by-step solution:
The question involves the quadratic equation. To the quadratic equation we can find the roots by factoring or by using the formula x=b±b24ac2ax = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}. So the equation is written as 3x212x3{x^2} - 12x.

In general, the quadratic equation is represented as ax2+bx+c=0a{x^2} + bx + c = 0, when we compare the above equation to the general form of equation the values are as follows. a=3 b=-12 and c=0. Now substituting these values to the formula for obtaining the roots we have
roots=(12)±(12)24(3)(0)2(3)roots = \dfrac{{ - ( - 12) \pm \sqrt {{{( - 12)}^2} - 4(3)(0)} }}{{2(3)}}
On simplifying the terms, we have
roots=12±14406\Rightarrow roots = \dfrac{{12 \pm \sqrt {144 - 0} }}{6}
Now add 144 to 0 we get
roots=12±1446\Rightarrow roots = \dfrac{{12 \pm \sqrt {144} }}{6}
The number 144 is a perfect square so we can take out from square root we have
roots=12±126\Rightarrow roots = \dfrac{{12 \pm 12}}{6}
Therefore, we have root1=12+126=246=4root1 = \dfrac{{12 + 12}}{6} = \dfrac{{24}}{6} = 4 or root2=12126=0root2 = \dfrac{{12 - 12}}{6} = 0.
The roots for the quadratic equation when we find the roots by using formula is given by (x – root1) (x – root 2)
Substituting the roots values, we have
(x4)(x0)\Rightarrow \left( {x - 4} \right)\left( {x - 0} \right)
On simplifying we have
x(x4)\Rightarrow x(x - 4)
This can also be solved by another method.
Consider the given equation 3x212x3{x^2} - 12x
Divide the equation by 3 we get
x24x{x^2} - 4x
Take x as a common so we have
x(x4)x(x - 4)

Hence, we have found the factors for the given equation

Note: The quadratic equation can be solved by using the factorisation method and we also find the roots by using the formula x=b±b24ac2ax = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}. While factorising we use sum product rule, the sum product rule is given as the product factors of the number c is equal to the sum of the factors which satisfies the value of b.