Question
Question: How do you factor \[3{x^2} - 12x\]?...
How do you factor 3x2−12x?
Solution
Here in this question, we have to find the factors, the given equation is in the form of a quadratic equation. This is a quadratic equation for the variable x. By using the formula x=2a−b±b2−4ac, we can determine the roots of the equation and factors are given by (x – root1) (x – root 2)
Complete step-by-step solution:
The question involves the quadratic equation. To the quadratic equation we can find the roots by factoring or by using the formula x=2a−b±b2−4ac. So the equation is written as 3x2−12x.
In general, the quadratic equation is represented as ax2+bx+c=0, when we compare the above equation to the general form of equation the values are as follows. a=3 b=-12 and c=0. Now substituting these values to the formula for obtaining the roots we have
roots=2(3)−(−12)±(−12)2−4(3)(0)
On simplifying the terms, we have
⇒roots=612±144−0
Now add 144 to 0 we get
⇒roots=612±144
The number 144 is a perfect square so we can take out from square root we have
⇒roots=612±12
Therefore, we have root1=612+12=624=4 or root2=612−12=0.
The roots for the quadratic equation when we find the roots by using formula is given by (x – root1) (x – root 2)
Substituting the roots values, we have
⇒(x−4)(x−0)
On simplifying we have
⇒x(x−4)
This can also be solved by another method.
Consider the given equation 3x2−12x
Divide the equation by 3 we get
x2−4x
Take x as a common so we have
x(x−4)
Hence, we have found the factors for the given equation
Note: The quadratic equation can be solved by using the factorisation method and we also find the roots by using the formula x=2a−b±b2−4ac. While factorising we use sum product rule, the sum product rule is given as the product factors of the number c is equal to the sum of the factors which satisfies the value of b.