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Question: How do you express \(2x+y=8\) in the form \(y=mx+b\), what is the slope and y intercept?...

How do you express 2x+y=82x+y=8 in the form y=mx+by=mx+b, what is the slope and y intercept?

Explanation

Solution

The equation of the line given in the above question is written as 2x+y=82x+y=8. To write it in the form of y=mx+by=mx+b, we have to separate the variable y on the LHS and write it in terms of the variable x on the RHS. So we have to subtract 2x2x from both the sides of the given equation 2x+y=82x+y=8 so that the given equation will reduce in the form of y=mx+by=mx+b. Since y=mx+by=mx+b is the slope intercept form, where mm is the slope and bb is the y-intercept, on comparing the obtained equation with y=mx+by=mx+b, we will get the respective values of the slope and the y intercept.

Complete step-by-step solution:
The equation given in the above question is
2x+y=8\Rightarrow 2x+y=8
For writing the above equation in the form of y=mx+by=mx+b, we subtract 2x2x from both the sides to get
2x+y2x=82x y=2x+8 \begin{aligned} & \Rightarrow 2x+y-2x=8-2x \\\ & \Rightarrow y=-2x+8 \\\ \end{aligned}
On comparing the above equation with the slope intercept form y=mx+by=mx+b, we get the respective values of the slope and the y intercept as
m=2\Rightarrow m=-2
And
b=8\Rightarrow b=8
Hence, the given equation is written in the form of y=mx+by=mx+b as y=2x+8y=-2x+8 and the slope and the y intercept are 2-2 and 88 respectively.

Note: We can also use the differentiation method to get the value of the slope. For this, we have to differentiate the both sides of the equation 2x+y=82x+y=8 with respect to x, and the value of the derivative dydx\dfrac{dy}{dx} will be equal to that of the slope. And for getting the value of the y intercept, we can put x=0x=0 in the given equation from which the obtained value of y will be equal to the y intercept.