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Question: How do you experimentally find the refractive index of the material of prism?...

How do you experimentally find the refractive index of the material of prism?

Explanation

Solution

You can start by explaining the apparatus needed for the experiment. Then explain how to calculate the value of the angle of deviation and the value of the angle of the prism. Then use the equation μ=sin[(A+D2]sinA2\mu = \dfrac{{\sin \left[ {\dfrac{{(A + D}}{2}} \right]}}{{\sin \dfrac{A}{2}}} to reach the solution.

Complete answer:
For determining the refractive index of the material of a prism you need the following material: A prism, piece of white chart or a white sheet, pins, scale, and a protractor.

Place the prism on the white chart in such a way that the triangular base of the prism is in contact with the chart.
Outline the triangular base of the prism on the white chart.
We obtain a triangle on the sheet, let’s name its vertices PP , QQ and RR .
Now, measure the angle between lines PQPQ and PRPR , let’s call this A\angle A .
Mark a point MM on the side PQPQ of the triangle (preferably on the center) and also draw a line perpendicular to PQPQ passing through the point MM .
Keep the center of the protractor at the point MM make a point AA at an angle of 3030^\circ . Join the point AA with the point MM .
Then place the prism back in its position on the white chart
Then place a pin at point AA and one at a point BB on the line AMAM .
Then look at the images from the opposite side of the prism and place two new pins in such a way that the 4 pins line up in a straight line.
Remove the pins and the prism and let’s name the two new points on the chart CC and DD respectively. Draw a line along with the points CC and DD till it meets the surface of the line PRPR . Let the point where it meets the line PRPR to be NN.
Draw a line at the point NN perpendicular to the line PRPR .
Extend both line AMAM and line DNDN till they intersect at the point OO .
The i\angle i and r\angle r in the figure represent the angle of incidence and the angle of emergence respectively.
The angle D\angle D in the figure represents the angle of deviation ( the angle that the incident ray makes with the emergent ray)
Calculations –
The refractive index of the material of the prism is calculated by using the following formula
μ=sin[(A+D2]sinA2\mu = \dfrac{{\sin \left[ {\dfrac{{(A + D}}{2}} \right]}}{{\sin \dfrac{A}{2}}}

Note:
In the solution above we only calculated the refractive index of the prism by keeping the angle of incidence as 3030^\circ , but it is common practice to take multiple angles of incidence and then follow the above process again and again. This gives us multiple values of the refractive index of the material of the prism. The average of these values will give us a more precise value of the refractive index.