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Question: How do you evaluate \(\tan \left( {\arctan \left( {0.88} \right)} \right)\)?...

How do you evaluate tan(arctan(0.88))\tan \left( {\arctan \left( {0.88} \right)} \right)?

Explanation

Solution

We are given a trigonometric expression. We have to find the value of the expression. First, evaluate the expression inside the brackets. Then, apply the trigonometric property to simplify the expression.

Complete step by step solution:
The given trigonometric expression is tan(arctan(0.88))\tan \left( {\arctan \left( {0.88} \right)} \right)

It can be written as tan(tan1(0.88))\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right)

The inverse of the function is opposite of the trigonometric function. Here, tan and tan1ta{n^{ - 1}} are opposite to each other.

When the function and its inverse is multiplied, then the result of multiplication is 1.

tan(tan1(0.88))=0.88 \Rightarrow \tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88

Hence the value of tan(arctan(0.88))\tan \left( {\arctan \left( {0.88} \right)} \right) is equal to 0.880.88.

Note: The students must note that we can also find the value of the given expression using the inverse tangent function data table.
First, the value of tan1(0.88)ta{n^{ - 1}}\left( {0.88} \right) is determined from the table.
tan1(0.88)=41.35\Rightarrow ta{n^{ - 1}}\left( {0.88} \right) = 41.35^\circ

Now, we will substitute 41.3541.35^\circ into the expression, we get:

tan(41.35) \Rightarrow \tan \left( {41.35^\circ } \right)

Then, we will determine the value of tan(41.35)\tan \left( {41.35^\circ } \right) from the data table.

tan(41.35)=0.88 \Rightarrow \tan \left( {41.35^\circ } \right) = 0.88

Therefore, tan(tan1(0.88))=0.88\tan \left( {ta{n^{ - 1}}\left( {0.88} \right)} \right) = 0.88