Question
Question: How do you evaluate \[{{\log }_{9}}729\]?...
How do you evaluate log9729?
Solution
Evaluating logarithmic equations we have to first check for the logarithm’s base. In this case we have the logarithm base as 9, so we will express the number given as a power of the base of the logarithm. Then using the logarithm formula, we will solve the equation.
Complete step-by-step solution:
Logarithm equation can be explained as an equation consisting of logarithm in the expression. To solve this expression, we will use the logarithm formula which is as follows:
Suppose we have, ax=b, then using logarithm to write this expression we have,
logab=x
Here, we have ‘a’ as the logarithm base. We can say that, ‘x’ is the logarithm of ‘b’ to the base ‘a’.
Let us understand this property using an example.
For example – we know that the product of two written thrice is eight. It can be written as:
23=8
If we use logarithm in the above expression, we can rewrite it as:
log28=3
So we have the base of the logarithm as 2, and since 8 can be written as two raised to the power 3. We get the following answer as 3.
⇒log223=3log22=3, as log22=1
According to the question we have, we have to solve for log9729,
We can see here that the base of the logarithm is 9, so we will write the number 729 as a power of 9. It can be written as:
729=9×9×9=93
Therefore, we have
log9729
⇒log993=3log99=3
Therefore, log9729=3
We can confirm this as log9729=3 would mean, 93=729 and which is correct.
Note: We can also solve the equation by taking,
log9729=y
As we know that, logab=x can also be written as ax=b. So, we have
9y=729
Writing the above expression as a power of same bases, we can have
⇒(32)y=(3)6
⇒(3)2y=(3)6
Since, the bases are same, we can equate their powers, we get
⇒2y=6
⇒y=3
Therefore, log9729=3